Exams Questions and Answers

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9	B) 605/9
C) 645/9	D) 700/9

Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

$\frac{1.8 x}{100} = 1.4$

x = $\frac{1.4 \times 100}{1.8} = \frac{700}{9} = 77 \frac{7}{9}$ .

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Filed Under: Percentage
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Q:

The non green heterotrophic plants of plant kingdom are

A) Algae	B) Fungi
C) Ferns	D) Both B & C

Answer & Explanation Answer: B) Fungi

Explanation:

The non green heterotrophic plants of plant kingdom are Fungi.

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Filed Under: General Science
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Q:

Select the synonym of

antagonize

A) alienate	B) placid
C) sync	D) serene

Answer & Explanation Answer: A) alienate

Explanation:

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Filed Under: English
Exam Prep: Bank Exams

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Q:

Where is the tomb of Sher Shah located?

A) Sasaram	B) Delhi
C) Kalinger	D) Sonargaon

Answer & Explanation Answer: A) Sasaram

Explanation:

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Filed Under: Indian History
Exam Prep: Bank Exams

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Q:

A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage?

A) 2.5%	B) 5%
C) 10%	D) 7.5%

Answer & Explanation Answer: C) 10%

Explanation:

According to the given data,

Let Cost price of the article be 'cp'

Then,

102.25 cp - 92 cp = 164 x 100

10.25 cp = 16400

cp = 1600

Now, if he sells at Rs. 1760

Profit = 1760 - 1600 = 160

Profit% = 160/1600 x 100 = 10%.

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Filed Under: Profit and Loss
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Q:

A motorboat takes half time to cover a certain distance downstream than upstream. What is the ratio between rate of current and rate of boat in still water?

A) 1 : 3	B) 3 : 2
C) 2 : 3	D) 3 : 1

Answer & Explanation Answer: A) 1 : 3

Explanation:

Let the speed of the boat in still water is 'w'

Speed of the current is 'c'

Let the distance between two places is 'd'

According to the question, motorboat takes half time to cover a certain distance downstream than upstream.

$\frac{d}{w + c} = \frac{1}{2} (\frac{d}{w - c})$

=> 2w - 2c = w + c

=> w = 3c

=> c : w = 1 : 3

Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3

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Filed Under: Boats and Streams
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Q:

The effects of any drug depend on

A) The amount taken at one time	B) The circumstances under which the drug is taken such as the simultaneous use of alcohol or other drugs, etc.
C) How the drug is consumed	D) All the above

Answer & Explanation Answer: D) All the above

Explanation:

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Filed Under: Biology
Exam Prep: Bank Exams

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Q:

Improve the bracketed part of the sentence.

Many such mishaps can be avoided if we (are) careful.

A) be	B) might be
C) were	D) no improvement

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