Exams


Q:

What is the median of the following list of numbers

 

55, 53, 56, 59, 61, 69, and 31 ?

A) 55 B) 56
C) 59 D) 61
 
Answer & Explanation Answer: B) 56

Explanation:
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Filed Under: Probability
Exam Prep: Bank Exams

1 9475
Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8 B) 25.2 and 50.4
C) 31.4208 and 62.8416 D) 33.12 and 66.24
 
Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

11 9472
Q:

How many days in 4 years?

A) 1460 B) 1461
C) 1462 D) 1459
 
Answer & Explanation Answer: A) 1460

Explanation:

Days in 4 years => 

Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years.

4 years => 365 + 365 + 365 + 366(Leap year)

4 years => 730 + 731 = 1461

 

Therefore, Number of Days in 4 Years = 1461 Days.

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Filed Under: Calendar
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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23 9468
Q:

In ∆PQR measure of angle Q is 90 deg. If cosecP = 17/15, and PQ = 0.8cm, then what is the length (in cm) of side QR?

 

A) 1.7   B) 2  
C) 2.5   D) 1.5
 
Answer & Explanation Answer: D) 1.5

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 9464
Q:

Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ?

A) Rs. 2000 B) Rs. 2100
C) Rs. 1900 D) Rs. 2150
 
Answer & Explanation Answer: A) Rs. 2000

Explanation:

Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A = P1 + r100n

(P+C.I) = P1 + 101002

(P+420) = P[11/10][11/10]

P-1.21P = -420

0.21P = 420

Hence, P = 420/0.21 = Rs. 2000

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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7 9462
Q:

Excretion is best described as the removal of

A) Undigested material from the digestive tract B) Metabolic wastes from a cell
C) Toxic wastes by the process of cyclosis D) Water molecules from dipeptide hydrolysis
 
Answer & Explanation Answer: B) Metabolic wastes from a cell

Explanation:

Excretion is best described as the removal of Metabolic wastes from a cell.

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

21 9460
Q:

Identify the diagram that best represents the relationship among the given classes.

Science, Physics, Chemistry

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:
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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

1 9458
Q:

The market price of an article was 40% more than its cost price. Rana was going to sell it at market price to a customer, but he showed Rana some defects in the article, due to which Rana gave him a discount of 28.57%. Next day he came again and showed Rana some more defects, hence he gave him another discount that was equal to 12.5% of the cost price. What was the approximate profit/loss to Rana ?

A) Loss of 12.5% B) Profit of 12.5%
C) Loss of 24.5% D) Profit of 22.5%
 
Answer & Explanation Answer: A) Loss of 12.5%

Explanation:

Let the cost price be Rs. 100
Then, market price is Rs. 140
Now, the first discount is of 28.57% Rs.140 =~ Rs. 40
Hence, its selling price = 140 - 40 = Rs. 100
Now since Rana is selling at cost price, any further discount will be equal to loss percentage.
The next dicount of 12.5% will be the loss percentage to Rana.

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Filed Under: Profit and Loss
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11 9444