Exams

Let the total Profit be Z.
Ramu's profit share is 2/3 of profit (i.e 2Z/3)
Ravi's profit is (Z-2Z/3) =Z/3
Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2

Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital.

Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit share
i.e. (X/6 x 16) / (2X/3 x Y) = 1/2

Solving the above equation, we get Y = 8.
So Ramu's money has been used for 8 months.

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

Interest received by L from K = 8% of half of Rs.40,000  

⇒8100×20000=1600  

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Let 'A' be the part of remaing profit that 'L' receives as his share.

 Total income of 'K' = only his share from the reamaing profit

                              = 'A', as both share equally.

Given income of L = Twice the income of K

--> (1600 + 14400 + A ) = 2A

--> A= Rs.16000

Thus total profit = 2A + Rs.14,400= 2(16000) + 14400 

                                                  = 32000 +14400 = Rs.46,400.

Ozone molecule has one single bond and one double bond.

P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.

Amount = 15225x1+41003

= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05

=> C.I. = 17126 - 15625 = Rs. 1901.05.

From the given data,

Virat : Rohit = 3 : 2

Rohit : Dhoni = 3 : 2

Ratio of runs scored by Virat, Rohit and Dhoni respectively

= 3 x 3 : 2 x 3 : 2 x 2

9 : 6 : 4

Runs scored by Virat = 9/19 x 285 = 135.

Monosaccharides, also called simple sugars, are the most basic units of carbohydrates. They are fundamental units of carbohydrates and cannot be further hydrolyzed to simpler compounds.

Hence, Monosaccharides can be classified according to the spatial arrangement of their atoms is true about Monosaccharides.