Exams Questions and Answers

Q:

Boron cannot form which one of the following anions?

(1) $B O_{2}^{-}$

(2) $B F_{6}^{3 -}$

(3) $B H_{4}^{-}$

(4) $B (O H)_{4}^{-}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: B) Option 2

Explanation:

Due to absence of low lying vacant d orbital in B, $s p^{3} d^{2}$ hybridization is not possible hence $B F_{6}^{3 -}$ will not formed.

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Filed Under: Chemistry
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104 67978

Q:

The percentage increase in the area of a rectangle, if each of its sides is increased by 20%

A) 22%	B) 33%
C) 44%	D) 55%

Answer & Explanation Answer: C) 44%

Explanation:

Let original length = x metres and original breadth = y metres.

Original area = xy sq.m

Increased length = $\frac{120}{100}$ and Increased breadth = $\frac{120}{100}$

New area = $\frac{120}{100} x * \frac{120}{100} y = \frac{36}{25} x y m^{2}$

The difference between the Original area and New area is:

$\frac{36}{25} x y - x y$

$\frac{11}{25} x y$ Increase % = $(\frac{\frac{11}{25} x y}{x y}) * 100$ = 44%

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Filed Under: Area
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107 67423

Q:

Epsom(England) is the place associated with

A) Snooker	B) Shooting
C) Polo	D) Horse racing

Answer & Explanation Answer: D) Horse racing

Explanation:

Epsom is a market town in Surrey, England, 22.0 km south-west of London.

Epsom Downs Racecourse holds The Derby, now a generic name for sports competitions in English-speaking countries. The town also gives its name to Epsom salts, extracted from mineral waters there.

epsom_england_is_the_place_associated_with1538367699.jpg image

Within the centuries-old boundaries is Epsom Downs Racecourse which features two of the five English Classic horse races; The Derby and The Oaks, which were first run in 1780 and 1779 respectively.

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445 67178

Q:

A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is :

A) 9.5 km/hr	B) 10 km/hr
C) 10.5 km/hr	D) 11 km/hr

Answer & Explanation Answer: B) 10 km/hr

Explanation:

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.

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Filed Under: Problems on Trains
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104 66356

Q:

Fastest Shorthand Writer was

A) Dr. G. D. Bist	B) J.R.D. Tata
C) J.M. Tagore	D) Khudada Khan

Answer & Explanation Answer: A) Dr. G. D. Bist

Explanation:

Dr. G. D. Bist, Guinness Record Holder, the first-ever Ph.D. in Stenography in the world.

fastest_shorthand_writer_-_Dr._G_._D_._Bist_1562583195.jpg image

He had achieved a highest speed of 250 w.p.m. in Shorthand.

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485 66293

Q:

Simplify the following :

$\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$ ?

A) 100	B) 1
C) 4	D) 0

Answer & Explanation Answer: A) 100

Explanation:

Given $\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$

It is in the form of

$\frac{a^{3} + b^{3} + c^{3} - 3 a b c}{a^{2} + b^{2} + c^{2} - a b - b c - c a}$ = a + b + c

Here a = 37, b = 35 & c = 28

=> a + b + c = 37 + 35 + 28 = 100

Therefore, $\frac{(37)^{3}+(35)^{3}+(28)^{3}-3x37x35x28}{(37)^{2}+(35)^{2}+(28)^{2}-37x35-35x28-37x28}$ = 100

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Filed Under: Simplification
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19 65252

Q:

Find the angle between the hour hand and the minute hand of a clock when the time is 3.25

A) 47.5 degrees	B) 57.5 degrees
C) 45.5 degrees	D) 55.5 degrees

Answer & Explanation Answer: A) 47.5 degrees

Explanation:

At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins.

Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = (25 x 30) / 60 = 12.5°

Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°

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Filed Under: Clocks
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162 65144

Q:

The compounded ratio of (2 : 3), (6: 11) and (11 :2) is

A) 1:2	B) 2:1
C) 11:24	D) 36:121

Answer & Explanation Answer: B) 2:1

Explanation:

Compounded Ratio :: When we compound two or more ratio's with each other through product or multiplication, the result is simply a compound ratio.

Thus, the product of two or more ratios; i.e, ab:cd is a ratio compounded of the simple ratios a:c and b:d.

Required compounded ratio = (2/3 x 6/11 x 11/2) = 2/1.

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Filed Under: Ratios and Proportions
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306 64805

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