Exams

If 'k' is number of students in P and 'l' is number of students in Q, then
From the given conditions, we have
=> k - 10 = l + 10 .......(1)
=> k + 20 = 2(l - 20) ....(2)

Solving these eqns, we get
k = 100 and l = 80.
Therefore, number of students in class Q is 80.

$$\begin{gathered} 2211 x 75 x 112 \\ => 222 x 75 x 112 \end{gathered}$$

 Total number of prime factors is (22+5+2) = 29

Let 'M' be the maximum marks in the examination.

Therefore, Madhu got 32% of M = 32M/100 = 0.32M
And Kumar got 42% of M = 42M/100 = 0.42M.
In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1)

The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2)

Now, Equating (1) and (2), we get
0.1M = 24 => M = 24/0.1 = 240
'M' is the maximum mark and is equal to 240 marks.
We know that Madhu got 32% of the maximum marks.
Therefore, Madhu got 32 x 240/100 = 76.8 marks.
We also know that Madhu got 8 marks less than the cut-off marks.

Therefore, the cut-off marks will be 8 marks more than what Madhu got
= 76.8 + 8 = 84.8.

The Mula-Mutha is a river in India, formed by the confluence of the Mula and Mutha rivers in the city of Pune, which later meets the Bhima River, which itself later meets the Krishna River and finally emptying to the Bay of Bengal.

For the input "A rolling stone gathers no moss", the steps followed are:

Step 1: rolling A stone gathers no moss

Step 2: rolling stone A gathers no moss

Step 3: rolling stone gathers A no moss

Step 4: rolling stone gathers no A moss

After 4 steps the fifth word is "A".

"G is father in law of D"
G+H means G is father of H
H is either son or daughter of G
H-R means H is sister of R
R@D means R is wife of D
so H and R are sisters
and daughters of G
so husband of R i.e. D is son in law of G
or G is father in law of D

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