Exams

Here I give you the first 30 Atomic elements names and their Atomic masses.

Atomic number      Element        Atomic mass
                             

        1                 Hydrogen           1

        2                  Helium              4

        3                 Lithium              6.94

        4                Beryllium            9.01

        5                  Boron               10.81

        6                Carbon               12.01

        7                Nitrogen             14.01

        8                Oxygen              15.99

        9                Fluorine              19.00

       10                Neon                 20.18

       11               Sodium               22.99

       12             Magnesium           25.31

       13             Aluminium            26.98

       14               Silicon                28.09

       15             Phosphorus           30.97

       16               Sulphur               32.07

       17               Chlorine              35.45

       18                Argon                 39.95

       19             Potassium              39.10

       20              Calcium                40.08

       21             Scandium              44.96

       22             Titanium               47.87

       23            Vanadium              50.94

       24             Chromium            24. 52

       25            Manganese            54.94

       26                Iron                  55.85

       27              Cobalt                 58.93

       28               Nickel                 58.69

       29              Copper                 63.55

       30                Zinc                   65.41

We know that zero can't be in hundreds place. But let's assume that our number could start with zero.

The formula to find sum of all numbers in a permutation is

111 x no of ways numbers can be formed for a number at given position x sum of all given digits

No of 1 s depends on number of digits

So,the answer us

111 x 20 x (0+1+2+3+4+5) = 33300

We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula.

Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0.

This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number.

So the sum for this is 11 x 4 x (1+2+3+4+5).
=660

Hope u understood why we use 4. Each number can be formed in 4x1 ways

So, the final answer is 33300-660 = 32640

Covalent bonds hold atoms together because the attraction between the positively charged nuclei and the negatively charged shared electrons is greater than the repulsions between the nuclei themselves.

VRAM or (video RAM), reference to any type of random access memory (RAM) is a dual-ported variant of dynamic RAM (DRAM) used to store the framebuffer in graphics adapters.