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Q:

Use continuity to evaluate the limit.

limx→128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx→128+x8+x = 8+128+12= 1.

 

 

 

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Filed Under: Simplification
Exam Prep: Bank Exams , CAT

0 50733
Q:

ΔABC is right angled at B. If cotA = 8/15, then what is the value of cosC ?

 

A) 15/8   B) 8/17  
C) 17/15   D) 15/17
 
Answer & Explanation Answer: D) 15/17

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 50704
Q:

Which species is a conjugate acid of OH- ?

 

A) H+ B) O2- 
C) OH D) H2O
 
Answer & Explanation Answer: D) H2O

Explanation:
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Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams

4 50701
Q:

Which of the following statement(s) is/are CORRECT?

 

I. (√11 + √2) > (√8 + √5)

II. (√10 + √3) > (√7 + √6

 

A) Only I B) Only II
C) Neither I nor II D) Both I and II
 
Answer & Explanation Answer: C) Neither I nor II

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 50695
Q:

Where does glucose breaks down into pyruvate?

 

A) Golgi bodies B) Cytoplasm
C) Chloroplast D) Protoplasm
 
Answer & Explanation Answer: B) Cytoplasm

Explanation:
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Filed Under: Biology
Exam Prep: Bank Exams

2 50666
Q:

22 - 33 + 43 - 62 = ?

 

A) 2 B) 3
C) 4 D) 5
 
Answer & Explanation Answer: D) 5

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 50639
Q:

Find the work done (in J) when a charge of 20 C moves across a potential difference of 4 V.

 

 

A) 5 B) 40
C) 80 D) 10
 
Answer & Explanation Answer: C) 80

Explanation:
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Filed Under: Physics
Exam Prep: Bank Exams

2 50610
Q:

A certain sum of money amounts to Rs 1008 in 2 years and to Rs 1164 in 3 ½  years. Find the sum and the rate of interest.

A) 800, 14% B) 800, 13%
C) 800, 12% D) 800, 19%
 
Answer & Explanation Answer: B) 800, 13%

Explanation:

S.I. for 1 ½ years = Rs (1164 - 1008) = Rs 156 . 

S.I. for 2 years = Rs (156 x 23 x 2)= Rs 208. 

Therefore, Principal = Rs (1008 - 208) = Rs 800. 

Now, P = 800, T= 2 and S.I. = 208.

Therefore, Rate = (100 x S.I.) / (P x T) = [ (100 x 208)/(800 x 2)]% = 13%

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Filed Under: Simple Interest
Exam Prep: GRE

145 50606