Exams Questions and Answers

Q:

Study the following table and answer the questions based on it.

Following table gives the expenditures of a company (in lakh rupees) per annum over the given years.

The total expenditure of the company over the items during the year 2001 is

A) Rs. 590 lakhs	B) Rs. 598 lakhs
C) Rs. 597 lakhs	D) Rs. 597.08 lakhs

Answer & Explanation Answer: D) Rs. 597.08 lakhs

Explanation:

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Filed Under: Table Charts
Exam Prep: Bank Exams

0 11148

Q:

Find the odd man out from the given alternatives ?

A) 97	B) 233
C) 437	D) 599

Answer & Explanation Answer: C) 437

Explanation:

Except 437 all others are prime numbers.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

33 11146

Q:

In a certain code ARCHIVE is written as DSBGFWJ. How is SYSTEMS is written in that code ?

A) TZTSTUN	B) TZTSTNF
C) TZTUTNF	D) TZTNTFS

Answer & Explanation Answer: B) TZTSTNF

Explanation:

ARC -> CRA ->(+1) DSB
H -> H ->(-1) G
IVE -> EVI ->(+1) FWJ

Similarly,

SYS -> SYS ->(+1) TZT
T -> T ->(-1) S
EMS -> SME ->(+1) TNF

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Filed Under: Alphabet Test
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

18 11142

Q:

At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ?

A) 5%	B) 6%
C) 4%	D) 3%

Answer & Explanation Answer: A) 5%

Explanation:

Given compound interest for 3 years = Rs. 1513.2

and simple interest for 5 years = Rs. 2400

Now, we know that C.I = $[P {(1 + \frac{R}{100})}^{n} - 1]$

=> 1513.2 = $[P {(1 + \frac{R}{100})}^{3} - 1]$ ...........(A)

And S.I = PTR/100

=> 2400 = P5R/100 ..................(B)

By solving (A) & (B), we get

R = 5%.

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

18 11130

Q:

The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M, with the maximum marks in each subject being 100.

The student who got the highest percentage of marks in P, C, M and B combined is

A) W	B) X
C) Y	D) Z

Answer & Explanation Answer: A) W

Explanation:

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Filed Under: Table Charts
Exam Prep: Bank Exams

1 11122

Q:

What was the day on 2nd Jan 1901 ?

A) Tuesday	B) Wednesday
C) Monday	D) Thursday

Answer & Explanation Answer: B) Wednesday

Explanation:

2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.

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Filed Under: Calendar
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

24 11109

Q:

Programs stored in ROM are called

A) Hardware	B) Firmware
C) Freeware	D) Software

Answer & Explanation Answer: B) Firmware

Explanation:

The programs which are as permanent as hardware and stored in ROM are known as Firmware.

Data stored in ROM can only be modified slowly, with difficulty, or not at all, so it is mainly used to store firmware (software that is closely tied to specific hardware, and unlikely to need frequent updates) or application software in plug-in cartridges.

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Filed Under: Computer
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

25 11107

Q:

The given table represents the marks obtained by four students W, X, Y and Z in four subjects P, C, B and M, with the maximum marks in each subject being 100.

Based on the given data, W's marks percentage in P, C and B combined is

which one of the following is a waterborne disease

A) 70	B) 75
C) 68	D) 72

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