CAT Questions

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Let work done by 1 man in i day be m

and Let work done by 1 boy in 1 day be b

From the given data,

4(5m + 3b) = 23

20m + 12b = 23....(1)

2(3m + 2b) = 7

6m + 4b = 7 ....(2)

By solving (1) & (2), we get

m = 1, b = 1/4

Let the number of required boys = n

6(7 1 + n x 1/4) = 45

=> n = 2.

In computing, the expansion card or board or accessory card is a printed circuit board that can be inserted into an electrical connector or expansion slot, on a computer motherboard, to add functionality to a computer system via the expansion bus.

A - A - A = 20
B - B - B = 15
C - C - C = 25

A = -20
B = -15
C = -25

=> A + B + C = (-20)+(-15)+(-25) = -20 - 15 - 25 = -60.

There is two sequence.
S(odd) P(Even) I(odd) D(even) E(odd) R(even) M(odd) A(even) N(odd)
For odd sequence, we want to write next alphabet of that
and for even, we want to write previous alphabet of that.

TOJCFQNZO is the Answer.

A Christian Priest wears cassock while a Graduate wears gown.

Hence, Cassock : Priest :: Gown : Graduate.

Cost price of the article is given by

= 400x100/(20+20)

= Rs.1000

We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
= P1+R100n= 87481-101003
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.

Therefore, the purchase price of the machine was Rs. 12,000.

Major fructose sources include all fruits and honey.