CAT Questions

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We know that I = PTR/100

11 = (2x30xR)/100

R = 18.333 %

The number of exhaustive events = 100 C₁ = 100.

We have 25 primes from 1 to 100.

Number of favourable cases are 75.

Required probability = 75/50 = 3/2.

I = (600x11x5)/100 = 330 Paise = Rs. 3.30

Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁)

As remaining person can be any one among three couples left.

Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅
= (10 x 6)/252 = 5/21

My fahter's mother's only daughter-in-law is my father's wife i.e. my mother. My mother's daughter is my sister. My sister's father is my father.

K's brother's wife's father-in-law is K's brother's father i.e. K's father. K's father's daughter is K's Sister.
L is daughter of K's sister => K is L's Uncle or Aunt.