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Q:

Most commonly used bleaching agent is

A) Chlorine B) Alcohol
C) Carbon dioxide D) Sodium Chloride
 
Answer & Explanation Answer: A) Chlorine

Explanation:

Chlorine is the most commonly used bleaching agent.

 

Bleaching agents are compounds which are used to remove color from substances such as textiles. A bleaching agent is a material that lightens or whitens a substrate through the chemical reaction. The bleaching reactions usually involve oxidative or reductive processes that degrade color systems.

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Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk

10 9262
Q:

A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ?

A) 9 and 3 kmph B) 6 and 7 kmph
C) 8 and 1 kmph D) 7 and 2 kmph
 
Answer & Explanation Answer: C) 8 and 1 kmph

Explanation:

Downstream speed = 72km/8hrs  = 9 kmph
upstream speed = 84km/12hrs = 7 kmph
speed of boat = avg of downstream and upstream speeds
speed of boat = (9+7)/2kmph = 8 kmph.
current speed = half of the difference of downstream and upstream speeds
currend speed = (9-7)/2kmph = 1 kmph

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank PO

19 9256
Q:

Excretion is best described as the removal of

A) Undigested material from the digestive tract B) Metabolic wastes from a cell
C) Toxic wastes by the process of cyclosis D) Water molecules from dipeptide hydrolysis
 
Answer & Explanation Answer: B) Metabolic wastes from a cell

Explanation:

Excretion is best described as the removal of Metabolic wastes from a cell.

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
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21 9255
Q:

Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ?

A) Rs. 2000 B) Rs. 2100
C) Rs. 1900 D) Rs. 2150
 
Answer & Explanation Answer: A) Rs. 2000

Explanation:

Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A = P1 + r100n

(P+C.I) = P1 + 101002

(P+420) = P[11/10][11/10]

P-1.21P = -420

0.21P = 420

Hence, P = 420/0.21 = Rs. 2000

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Filed Under: Compound Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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7 9255
Q:

Four persons can cross a bridge in 3,7,13,17 minutes.Only two can cross at a time.Find the minimum time taken by the four to cross the bridge ?

A) 17 minutes B) 20 minutes
C) 34 minutes D) 12 minutes
 
Answer & Explanation Answer: B) 20 minutes

Explanation:

First send 17 and 7. After 7 minutes, 7 is at finish and 17 needs 10 more minutes to complete his travel. now send 13. After 10 minutes 17 reaches finish and 13 needs 3 more minutes to complete. now send 3. both 3 and 13 reach destination at the same time after 3 minutes. hence the time taken is 7+10+3=20 minutes.

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Filed Under: Logic
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

15 9242
Q:

A person is asked to put in a basket one apple when ordered 'one', one guava when ordered 'two', one orange whe ordered 'three' and is asked to take out from the basket one apple and one guava both when ordered 'four'. The ordered sequence executed by the person is as follows :

1 2 3 3 2 1 4 2 3 1 4 2 2 3 3 1 4 1 1 3 2 3 4


1. How many apples will be there in the basket at the end of the above order sequence ?
      (a) 4     (b) 3     (c) 2    (d) 1


2. How many fruits will be there in the basket at the end of the above order sequence ?
      (a) 13   (b) 17   (c) 9    (d) 11

Answer

1. Answer (c)


Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it.


Required number of apples = number of 1's - number of 4's = 6 - 4 = 2


2. Answer (d)


Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it.


Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's)


= 6 + 6 + 7 - (2x4)
= 19 - 8
= 11.

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Subject: Number, Ranking and Time Sequence Test Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

13 9242
Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8 B) 25.2 and 50.4
C) 31.4208 and 62.8416 D) 33.12 and 66.24
 
Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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11 9237
Q:

Careful is to Cautious as Boastful is to

A) Surprisingly B) Happily
C) Arrogant D) Humble
 
Answer & Explanation Answer: C) Arrogant

Explanation:

Here the given words Careful and Cautious are related in such a way that they are Synonyms of each other.

Therefore, Similarly Boastful is synonym to the word Arrogant.

Happily and Humble are Antonyms of Boastful and Surprisingly is the word not related to Boastful in any way.

 

So, Careful is to Cautious as Boastful is to Arrogant.

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT , GRE , TOEFL
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7 9236