CAT Questions

Q:

Every computer on the internet is known as

A) Client B) Modem
C) Server D) Host
 
Answer & Explanation Answer: D) Host

Explanation:

Every computer on the internet needs a string called Internet Protocol (IP address) to perform its work. So Every computer on the internet is known as Host.

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Filed Under: Computer
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Q:

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age og the youngest child ?

A) 8 yrs B) 16 yrs
C) 6 yrs D) 4 yrs
 
Answer & Explanation Answer: D) 4 yrs

Explanation:

Let the age of the youngest child is 'X' years.
Then the child elder than the yongest is 'X + 3' yrs
Since each have 3yrs difference upto 5 children
And given that
=> X + X+3 + X+6 + X+9 + X+12 = 50
=> 5X + 30 = 50
=> X = 4 yrs.

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Filed Under: Problems on Ages
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Q:

Out of sixty students, there are 14 who are taking Economics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class ?

A) 8/15 B) 7/15
C) 1/15 D) 4/15
 
Answer & Explanation Answer: B) 7/15

Explanation:

Given total students in the class = 60
Students who are taking Economics = 24 and
Students who are taking Calculus = 32
Students who are taking both subjects = 60-(24 + 32) = 60 - 56 = 4
Students who are taking calculus only = 32 - 4 = 28
probability that a randomly chosen student from this group is taking only the Calculus class = 28/60 = 7/15.

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Q:

The age of Manisha and Sudeshna are in the ratio of 5 : 6 respectively. After 8 years the ratio  of their ages will be 7 : 8. What is the difference of their ages ?

A) 6 B) 4
C) 8 D) 10
 
Answer & Explanation Answer: B) 4

Explanation:

Let the age of Manisha and Sudeshna is 5x and 6x years respectively.

According to the given data,

5x+8/6x+8 = 7/8

42x + 56 = 40x + 64

x = 4

Required Difference of their ages = (6 × 4)  –  (5 × 4)

= 4 years.

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Q:

I, J , K and L are all distinct individual. I is the daughter of J. J is the son of K and 'K' is the father of L. If B is the son of J and B has one brother, 'D'. Then which of the following statements is/ are true ?

I. I is the sister of D.

II. D and B are brother.

III. K is the grand father of D.

A) Only I B) I & II
C) Only III D) All of these
 
Answer & Explanation Answer: D) All of these

Explanation:

   K

   |

   J -- L

   |

   I -- D -- B

Here I is female

J, K, L & D , B are males

Then from the above conditions,

All of the given statements are true.

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Q:

A mother can do a certain job in x hours. Her daughter takes twice as long to do the job. Working together, they can do the job in 6 hours. How many hours does the mother take to do the job ?

A) 3 B) 6
C) 9 D) 12
 
Answer & Explanation Answer: C) 9

Explanation:

The mother completes the job in x hours.
So, the daughter will take 2x hours to complete the same job.

 

In an hour, the mother will complete 1/x of the total job.
In an hour, the daughter will complete 1/2x of the total job.

 

So, if the mother and daughter work together, in an hour they will complete 1/x + 1/2x of the job.
i.e., in an hour they will complete 3/2x of the job.

 

The question states that they complete the entire task in 6 hours if they work together.
i.e., they complete 1/6 th of the task in an hour.

 

Equating the two information, we get 3/2x = 1/6
By solving for x, we get 2x = 18 or x = 9.

 

The mother takes 9 hours to complete the job.

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Filed Under: Time and Work
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Q:

Virus doubles every 3 mins. It is 'K' in 1 hour, when was it K/4 ?

A) 29 min B) 25 min
C) 54 min D) 57 min
 
Answer & Explanation Answer: C) 54 min

Explanation:

If virus is K in 1hr i.e 60 min
then in 57 min it was K/2 as it doubles every 3 minutes
=> In 54 min it was K/4.
At 54 minutes it was K/4.

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Filed Under: Arithmetical Reasoning
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Q:

Sreya bought a plot for Rs. 6,00,000,  then sold half of the plot at 10 % profit and rest at 15% profit. What is the total profit % that Sreya gain? 

A) 13.8 % B) 11.4 %
C) 12.5 % D) 14.5 %
 
Answer & Explanation Answer: C) 12.5 %

Explanation:

10% profit at half plot = 600000/2 x 10/100 = Rs. 30,000

15% profit at remaining half plot = 600000/2 x 15/100 = Rs. 45,000

Now, total profit = 30000 + 45000 = 75000

Profit % = 75000/600000 x 100 = 12.5 %

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Filed Under: Profit and Loss
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