Common Admission Test (CAT) Questions and Answers with Explanation

Q:

Select the related word/letters/number from the given alternatives.

? : GA : : QR : JI

A) KN	B) RS
C) NQ	D) TZ

Answer & Explanation Answer: D) TZ

Explanation:

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Q:

A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes?

A) 4%	B) 5%
C) 6%	D) 8%

Answer & Explanation Answer: A) 4%

Explanation:

SP of first article = Rs.1000

Profit = 20%

$C P = S P x \frac{100}{100 + P %} = R s . \frac{2500}{3}$

SP of Second Article = Rs.1000

Loss = 20%

$C P = S P x \frac{100}{100 - L %} = R s . 1250$

So, Total SP = Rs.2000; Total CP = Rs.6250/3

As the CP is more than SP, he makes a loss.

Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3)

So, Loss Percent = Lossx100/CP = 4%

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Q:

Find the wrong number in the given number series?

5, 8, 40, 90, 664

A) 8	B) 40
C) 90	D) 664

Answer & Explanation Answer: B) 40

Explanation:

The given number series is 5, 8, 40, 90, 664

5

5 - 1 x 2 = 8

8 - 3 x 4 = 20 (NOT 40)

20 - 5 x 6 = 90

90 - 7 x 8 = 664

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Q:

Which of the following is a popular programming language for developing multimedia webpages.

A) COBOL	B) Java
C) BASIC	D) Assembler

Answer & Explanation Answer: B) Java

Explanation:

Java is a general-purpose computer-programming language that is concurrent, class-based, object-oriented, and specifically designed to have as few implementation dependencies as possible.

Which_of_the_following_is_a_popular_programming_language_for_developing_multimedia_webpages1548652333.jpg image

Java is used to develop mobile apps, web apps, desktop apps, games and much more...

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Q:

Find the next number in the given number series?

2, 19, 0, 21, –2, ?

A) 23	B) 25
C) 27	D) 29

Answer & Explanation Answer: A) 23

Explanation:

The given number series 2, 19, 0, 21, –2, ? follows a pattern,

2

2 + 17 = 19

19 - 19 = 0

0 + 21 = 21

21 - 23 = -2

-2 + 25 = 23

Hence, the next number in the series is 23.

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Q:

Choose the word which gives best meaning to the sentence from the given options.

His recent success ______ him more arrogant than what he used to be

A) make	B) have make
C) was making	D) has made

Answer & Explanation Answer: D) has made

Explanation:

HIS RECENT SUCCESS HAS MADE HIM MORE ARROGANT THAN WHAT HE USED.

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Q:

Statement :

The byproducts obtained from animals such as hairs, skins, horns, etc. contain at least 45 per cent food protein. Indian scientists have developed methods to segregate 50 per cent of this protein. They have used an enzyme developed in Russia for destruction of soya-proteins.

Conclusions:

A. Indian scientists cannot develop enzymes.

B. If a suitable method involving less cost is developed then many more food protein would be obtained.

A) Only A follows	B) Only B follows
C) Neither A nor B follows	D) Both A & B follows

Answer & Explanation Answer: C) Neither A nor B follows

Explanation:

There is no indication that Indian scientists are incapable of developing enzymes. There could be any number of reasons why Indian scientists used Russian enzymes.

So conclusion A does not follow.

In addition, cost is not discussed in the passage at all. There is no mention of a correlation between cost and extraction of proteins.

Thus, conclusion B does not follow either.

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Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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