CAT Questions

Q:

Choose the word which gives best meaning to the sentence from the given options.

His recent success ______ him more arrogant than what he used to be

A) make B) have make
C) was making D) has made
 
Answer & Explanation Answer: D) has made

Explanation:

HIS RECENT SUCCESS HAS MADE HIM MORE ARROGANT THAN WHAT HE USED.

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Q:

7 is to 34 as 5 is to

A) 33 B) 24
C) 54 D) 41
 
Answer & Explanation Answer: D) 41

Explanation:

We can get this by any of two explanations.

 

Answer 1: 41

7 = 3 + 4  = 34

Similarly, 5 = 4 + 1  = 41

 

Answer 2 :  41

7 - 3 = 4  => 34

Similarly, 5 - 4 = 1  => 41

 

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Filed Under: Arithmetical Reasoning
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Q:

Find the next number in the given number sequence

200, 200, 100, 300, 75, ?

A) 150 B) 175
C) 250 D) 375
 
Answer & Explanation Answer: D) 375

Explanation:

The given number series is 200, 200, 100, 300, 75, ?

It follows a pattern that,

200

200 x 1 = 200

200 / 2 = 100

100 x 3 = 300

300 / 4 = 75

75 x 5 = 375

 

Hence, the next number in the given number sequence is 375.

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Filed Under: Number Series
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12 42458
Q:

Transition : Change :: Immobility :  ?

A) Stillness B) Liveliness
C) Action D) Busyness
 
Answer & Explanation Answer: A) Stillness

Explanation:

Given Transition is to Change, and we know that Transition and change are Synonyms. Similarly, Immobility means not moving and synonym of immobility are motionlessness, stillness,...

 

Hence, Transition is to change as immobility is to stillness.

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Filed Under: Analogy
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Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

 

2. How many students are there in Class IX in the school?

 A. 336                      B.189                       C. 335                         D. 430

 

3. Which section has the maximum pass percentage in at least one of the two examinations?

  A. A Section            B. B Section            C. C Section               D. D Section

 

4. Which section has the maximum success rate in annual examination?

 A. A Section             B. B Section            C. C Section               D. D Section

 

5. Which section has the minimum failure rate in half yearly examination?

 A. A section             B. B section             C. C section               D. D section

 

Half yearly examinations were more difficult.
If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C 


 Explanation -  Number of students who passed half-yearly exams in the school 


= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true. 


 


 2. ANSWER : D 


 Explanation -  Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class: 


 = (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430. 


 


 3. ANSWER : D 


 ExplanationPass percentages in at least one of the two examinations for different sections are:


  For Section A = 14+6+6428+14+6+64×100 = 84112×100% = 75%


 For Section B =12+17+5523+12+17+55×100  % = 78.5%


 For Section C = 8+9+4617+8+9+46×100%= 78.75%


 For Section D = 13+15+7627+13+15+76×100%= 79.39%


  Clearly ,the pass percentage is maximum for Section D 


 


  


 4. ANSWER : A


 Explanation - Total number of students passed in annual exams in a section 


= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section


 Success rate in annual exams in Section A= 14+64112 × 100% = 69.64%


 Similarly, success rate in annual exams in:


 Section B = 12+55107×100% =  62.62% 


 Section C = 8+4680×100% = 67.5% 


 Section D = 89131×100% = 67.94% 


 Clearly, the success rate in annual examination is maximum for Section A. 


 


  


 5. ANSWER : D 


 Explanation - Total number of failures in half-yearly exams in a section


  = [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section


 Failure rate in half-yearly exams in Section A %= 37.5 %


 Similarly, failure rate in half-yearly exams in:


  Section B = 32.71%


  Section C = 31.25%


  Section D = 30.53%


  Clearly, the failure rate is minimum for Section D.


 = (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)


 = (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)


 = 288.


 


 Also, Number of students who passed annual exams in the school


 = (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)


 = (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)


 = 288.


 


Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.


Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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138 42321
Q:

Who was the first indian ruler to apply the western methods to his administration?

A) Haider Ali B) Tipu Sultan
C) Murshid Quil Khan D) Malhar Rao Holkar
 
Answer & Explanation Answer: B) Tipu Sultan

Explanation:

Tipu Sultan was the first indian ruler to apply the western methods to his administration. Sultan Fateh Ali Sahab Tipu, also known as the Tipu Sahib, was a ruler of the Kingdom of Mysore. He was the eldest son of Sultan Hyder Ali of Mysore.

Tipu-Sultan1533103459.jpg image

Tipu Sultan introduced a number of administrative innovations during his rule, including his coinage, a new Mauludi lunisolar calendar, and a new land revenue system which initiated the growth of the Mysore silk industry.

He was one of the few South Indian kings to provide stiff resistance to British imperialism, along with Hyder Ali. He is applauded as a ruler who fought against British colonialism. Similarly he has been a controversial figure and criticized for his atrocities against Hindus, Christians, and Mappla Muslims.

 

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Q:

Which of the following is a popular programming language for developing multimedia webpages.

A) COBOL B) Java
C) BASIC D) Assembler
 
Answer & Explanation Answer: B) Java

Explanation:

Java is a general-purpose computer-programming language that is concurrent, class-based, object-oriented, and specifically designed to have as few implementation dependencies as possible.

 

Which_of_the_following_is_a_popular_programming_language_for_developing_multimedia_webpages1548652333.jpg image


Java is used to develop mobile apps, web apps, desktop apps, games and much more...

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Q:

What is the common ratio of the following geometric sequence?

4, 2, 1, 0.5, 0.25, 0.125,...

A) 0.5 B) -1
C) 1.5 D) -0.5
 
Answer & Explanation Answer: A) 0.5

Explanation:

In mathematics, a geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

 

Herein the given sequence, 4, 2, 1, 0.5, 0.25, 0.125,...

Common Ratio r = 2/4 = 1/2 = 0.5/1 = 0.25/0.5 = 0.125/0.25 == 0.5.

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Filed Under: Problems on Numbers
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