AIEEE Questions

---

Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120

For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120

So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120
So remaining tank = 13/120

Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.
So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes

Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

Angle between hands of a clock

When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock

=> 30H-M5+M2 degrees

Here H = 4, M = 15 and the minute hand is behind the hour hand.

Hence the angle

 = 30[4-(15/5)]+15/2 = 30(1)+7.5 = 37.5 degrees

Let the speed of boat and stream be x and y kmph respectively.

According to question

d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i)

and 2d/x-y = 7...... (ii)

From eq. (i) and (ii)

2d/x+y = 7/2

Hence, Amith will take to row 2d km distance downstream in 7/2 hrs

= 3.5 hrs

= 3 hrs 30 min.

1. Answer (c)

Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it.

Required number of apples = number of 1's - number of 4's = 6 - 4 = 2

2. Answer (d)

Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it.

Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's)

= 6 + 6 + 7 - (2x4)
= 19 - 8
= 11.

Speed of the current = 24-16/2

= 8/2

= 4 km/hr.

Let the sum be Rs. S.
(S x 18 x 2)/100 - (S x 12 x 2)/100 = 840 => 36S/100 - 24S/100 = 840

=> 12S/100 = 840 => S = 7000.

The Dronacharya Award, formally known as Dronacharya Award for Outstanding Coaches in Sports and Games, is sports training honour of the Republic of India. The award is named after Drona, often referred as "Dronacharya" or "Guru Drona", a character from the Sanskrit epic Mahabharata of ancient India.