AIEEE Questions and Answers with Explanation

Q:

The respective ratio between the speed of a bike, a van and lorry is 3 : 5 : 2. The speed of the van is 250 percent of the speed of the lorry which covers 360 km in 12 hours. What is the average speed of the bike and the van together?

A) 60 kmph	B) 62 kmph
C) 64 kmph	D) 63 kmph

Answer & Explanation Answer: A) 60 kmph

Explanation:

Speed of lorry = $\frac{360}{12}$ = 30 kmph

Speed of van = $\frac{250}{100} x 30$ = 75 kmph

Speed of bike = $\frac{3}{5} x 75$ = 45 kmph

Therefore, now required average speed of bike and van = $\frac{75 + 45}{2}$ = 60 kmph.

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Filed Under: Time and Distance
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12 8356

Q:

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?

A) 6	B) 8
C) 4	D) 9

Answer & Explanation Answer: C) 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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Filed Under: HCF and LCM
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17 8347

Q:

The degree of dissociation ( $α$ ) of a weak electrolyte, $A_{x} B_{y}$ is related to van't Hoff factor (i) by the expression:

$1 . α = \frac{x + y + 1}{i - 1}$

$2 . α = \frac{x + y - 1}{i - 1}$

$3 . α = \frac{i - 1}{x + y + 1}$

$4 . α = \frac{i - 1}{x + y - 1}$

A) 1 is correct	B) 2 is correct
C) 3 is correct	D) 4 is correct

Answer & Explanation Answer: D) 4 is correct

Explanation:

Van't Hoff factor (i) = $\frac{O b s e r v e d C o l l i g a t i v e P r o p e r t y}{N o r m a l C o l l i g a t i v e P r o p e r t y}$

$\begin{matrix} A_{x} B_{y} \\ 1 - α \end{matrix} \to \begin{matrix} x A^{+ y} \\ x α \end{matrix} + \begin{matrix} y B^{- x} \\ y α \end{matrix}$

Total Moles = $1 - α + x α + y α$ = $1 - α (x + y - 1)$

$i = \frac{1 + α (x + y - 1)}{1}$

$\Rightarrow α = \frac{i - 1}{x + y - 1}$

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Filed Under: Chemistry
Exam Prep: AIEEE

6 8340

Q:

Firm : Flabby :: Piquant : ?

A) Pleasant	B) Bland
C) Small	D) Salty

Answer & Explanation Answer: B) Bland

Explanation:

The words in each pair are antonyms of each other.

Hence, Firm : Flabby :: Piquant : Bland.

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams
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8 8322

Q:

Porcupine : Rodent :: Mildew : ?

A) Insect	B) Fungus
C) Pathogen	D) Germ

Answer & Explanation Answer: B) Fungus

Explanation:

Porcupine is a rodent and mildew is a fungus.

Hence, Porcupine : Rodent :: Mildew : Fungus.

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Filed Under: Analogy
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14 8321

Q:

Find the errors in the below given A, B, C & D sentences.

$\frac{F o r m e r p r i m e m i n i s t e r r u l e d h i m s e l f o u t}{(A)} / \frac{a s a n a l t e r n a t i v e r i g h t w i n g c a n d i d a t e f o r h i s p a r t y c o l l e a g u e}{(B)} /$

$\frac{w h o s e c a m p a i g n h a s b e e n t h r o w n i n t o c h a o s}{(C)} / \frac{b y a f a k e j o b s s c a n d a l}{(D)}$

A) A & C	B) B & D
C) A & D	D) C & B

Answer & Explanation Answer: C) A & D

Explanation:

A) As prime minister is an honorable person it must start with an Article 'The'.

D) a fake jobs => a indicates it is singular, so job will come.

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Filed Under: Verification of Truth of the statement
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13 8320

Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres	B) 100 litres
C) 150 litres	D) 120 litres

Answer & Explanation Answer: D) 120 litres

Explanation:

$\frac{w i n e (l e f t)}{w i n e (a d d e d)} = \frac{343}{169}$

It means $\frac{w i n e (l e f t)}{w i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ (since 343 + 169 = 512)

Thus, $343 x = 512 x {(1 - \frac{15}{k})}^{3}$

$\frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

$(1 - \frac{15}{k}) = \frac{7}{8} = (1 - \frac{1}{8})$

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
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29 8319

Q:

Which compound contains both ionic and covalent bonds?

A) NaNO3	B) CaSO4
C) NH4Cl	D) All of the above

Answer & Explanation Answer: D) All of the above

Explanation:

Here all the given compounds have both ionic and covalent bonds.

NaNO3 - In Sodium nitrate, Nitrate is covalently bonded as nitrogen is bonded with 3 oxygen atoms. And this nitrate is ionically bonded with sodium.

CaSO4 - In Calcium sulphate, sulphate is covalently bonded as sulphur is bonded with 4 oxygen atoms. And this sulphate is ionically bonded with calcium.

NH4Cl - In Ammonium chloride, ammonium is covalently bonded as nitrogen is bonded with 4 hydrogen atoms. And this ammonium is ionically bonded with chlorine.

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Filed Under: Chemistry
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5 8311

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