AIEEE Questions and Answers with Explanation

Q:

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

A) 28 kmph	B) 24 kmph
C) 26 kmph	D) 32 kmph

Answer & Explanation Answer: B) 24 kmph

Explanation:

Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 8022

Q:

The degree of dissociation ( $α$ ) of a weak electrolyte, $A_{x} B_{y}$ is related to van't Hoff factor (i) by the expression:

$1 . α = \frac{x + y + 1}{i - 1}$

$2 . α = \frac{x + y - 1}{i - 1}$

$3 . α = \frac{i - 1}{x + y + 1}$

$4 . α = \frac{i - 1}{x + y - 1}$

A) 1 is correct	B) 2 is correct
C) 3 is correct	D) 4 is correct

Answer & Explanation Answer: D) 4 is correct

Explanation:

Van't Hoff factor (i) = $\frac{O b s e r v e d C o l l i g a t i v e P r o p e r t y}{N o r m a l C o l l i g a t i v e P r o p e r t y}$

$\begin{matrix} A_{x} B_{y} \\ 1 - α \end{matrix} \to \begin{matrix} x A^{+ y} \\ x α \end{matrix} + \begin{matrix} y B^{- x} \\ y α \end{matrix}$

Total Moles = $1 - α + x α + y α$ = $1 - α (x + y - 1)$

$i = \frac{1 + α (x + y - 1)}{1}$

$\Rightarrow α = \frac{i - 1}{x + y - 1}$

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Filed Under: Chemistry
Exam Prep: AIEEE

6 8018

Q:

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

A) 400 m	B) 300 m
C) 500 m	D) 600 m

Answer & Explanation Answer: A) 400 m

Explanation:

Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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7 8017

Q:

Who are the primary users of SCM systems?

A) Accounting, finance, logistics, and production	B) Customers, resellers, partners, suppliers, and distributors
C) Sales, marketing, customer service	D) All of the above

Answer & Explanation Answer: B) Customers, resellers, partners, suppliers, and distributors

Explanation:

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Filed Under: Computer
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5 8015

Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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16 8012

Q:

What kind of dress can never be worn?

Answer

ADDRESS is what the kind of dress can never be worn by anyone.

Workspace

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Subject: Word Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GRE , TOEFL
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9 8010

Q:

Which statement best describes an $O_{3}$ molecule?

A) The double bond in ozone switches back and forth between the two outer oxygen atoms	B) An ozone molecule contains one single bond and one double bond
C) Each atom in ozone is connected to another atom by 1.5 bonds.	D) None

Answer & Explanation Answer: B) An ozone molecule contains one single bond and one double bond

Explanation:

Ozone molecule has one single bond and one double bond.

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Filed Under: General Science
Exam Prep: AIEEE , GATE
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8 8006

Q:

The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is ?

A) 2(6!)	B) 6! x 7
C) 6! x ⁷P₆	D) None

Answer & Explanation Answer: C) 6! x ⁷P₆

Explanation:

We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! x ⁷P₆

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Filed Under: Permutations and Combinations
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6 8000

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