AIEEE Questions

Q:

To what kingdom do common bacteria belong

A) Archaea B) Protista
C) Eubacteria D) All the above
 
Answer & Explanation Answer: C) Eubacteria

Explanation:

There are two kingdoms of bacteria. They are

1. Eubacteria  and 

2. Archaea

 

The members of these two kingdoms appear similar in shape and appearance, even under the extreme magnification of the electron microscope . However, they are very different from each other in a number of molecular and biochemical aspects. It is these differences that have resulted in the microorganisms being grouped into separate kingdoms.

 

For example, eubacteria contain the rigid, stress-bearing network known as the peptidoglycan . The only exceptions are the bacteria from the genera Mycoplasma and Chlamydia. Archaebacteria do not contain peptidoglycan. Instead, they contain a different structure that is called pseudomurein.

 

The common bacteria belongs to Eubacteria kingdom.

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Filed Under: Biology
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6 6148
Q:

A bill presented in Parliament becomes an Act after -

A) The Prime Minister has signed it B) The Supreme Court has declared it to be within the competence of the Union Parliament
C) The President has given her/his assent D) It is passed by both the Houses
 
Answer & Explanation Answer: C) The President has given her/his assent

Explanation:
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Filed Under: Indian Politics
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11 6145
Q:

 'International Plastic Bag Free Day' is observed on which date ?

A) 3 July B) 4 July
C) 6 July D) 5 July
 
Answer & Explanation Answer: A) 3 July

Explanation:

International Plastic Bag Free Day was observed on 3rd of July 2017. It has been dedicated to heightening awareness about plastic and disposable carrying devices. International Plastic Bag Free Day gives us an opportunity to remind ourselves, and others, that every action we take, and every bag we dispose of effects the lives of everyone in the world for generations to come.

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6 6143
Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000 B) Rs.4500
C) Rs.7500 D) Rs.5000
 
Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
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9 6140
Q:

In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together?

A) 360 B) 720
C) 120 D) 840
 
Answer & Explanation Answer: A) 360

Explanation:

CAPITAL = 7

 

Vowels = 3 (A, I, A)

 

Consonants = (C, P, T, L)

 

5 letters which can be arranged in  5P5=5!

 

Vowels A,I = 3!2!

 

No.of arrangements = 5! x 3!2!=360

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Filed Under: Permutations and Combinations
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4 6130
Q:

A Cricket team of 23 people all shake hands with each other exactly once. How many hand shakes occur ?

A) 142 B) 175
C) 212 D) 253
 
Answer & Explanation Answer: D) 253

Explanation:

The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on...
So,
22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.

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4 6130
Q:

A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?

A) 6.24 sec B) 6.58 sec
C) 7.325 sec D) 7.65 sec
 
Answer & Explanation Answer: D) 7.65 sec

Explanation:

Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec

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Filed Under: Problems on Trains
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8 6123
Q:

What is the smallest number of ducks that could swim in this formation - two ducks in front of a duck, two ducks behind a duck and a duck between two ducks ?

A) 3 B) 5
C) 7 D) 9
 
Answer & Explanation Answer: A) 3

Explanation:
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Filed Under: Arithmetical Reasoning
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8 6108