AIEEE Questions

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The given series follows,

2

2 x 2 = 4

4 x 3 = 12

12 x 4 = 48

48 x 5 = 240.

The structural unit of compact bone is Osteons or Haverisan systems.

1 to 300 = 300 numbers
squares btwn 1 to 300 = 1,4,9,16,25,36,49.....289 i.e, total 17
cubes = 1,8,27,64,125,216 i.e, 5
now 1 and 64 are common so total numbers that should be removed ( 17+5-2= 20 )
total 20 term removed so 300th term would be 320

0.46 = 46/100 = 23/50.

Sum of the numerator and denominator is 23 + 50 = 73

Here by trial and error method, we can obseve that

404404 = 404 x 1001; 415415 = 415 x 1001, etc.

So, any number of this form is divisible by 1001.

A pen name is nothing but a nick name used by the writer when publishing books instead of using their real names. 

Kamala Kanta was the pen name of Bankim Chandra Chatterjee who lived from 1838 - 1894. He was a Bengali author, poet who wrote Indian national anthem Vandemataram.

The Chipko movement or Chipko Andolan refers to a forest conservation movement or deforestation. In modern india, it began in 1973 in the state of Uttar Pradesh (now Uttarakhand). Sunderlal Bahuguna and 84 villagers risked their lives to protect the forest trees from being felled on the order of the maharaja (king) and went on to become a rallying point for many future environmental movements all over the world it created a precedent for starting of nonviolent protest in India, and its success meant that the world immediately took notice of this non violent movement, which was to inspire in time many such eco-groups by helping to slow down the rapid deforestation, expose vested interests, increase ecological awareness, and demonstrate the viability of people power. Above all, it stirred up the existing civil society in India, which began to address the issues of tribal and marginalized people.

Chipko type movement dates back to 1730 AD when in a khejarli village of Rajasthan, 363 people sacrificed their lives to save khejari trees.

Unit digit of this expression is always 1 as the base ends with 1. 

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

Therefore, last two digits of 2151415 is 51.