AIEEE Questions

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The digits on either side of the letter in each of the groups 1P6, 2T0, and 1R8 indicate the place value of the letter in the alphabet.

This pattern is not followed by 2Y4.

The two major types of computer chips are Microprocessor and Primary memory chips.

Let the heights of Cat, Table and Turtle be C, T & R respectively.

From the above given figure,

C + T - R = 170 ......(a)

R + T - C = 130 ......(b)

Adding above eqns (a) & (b), we get

2T = 300

T = 150 cm

Hence, the height of the table is 150 cm.

The Feroz Shah Kotla Ground is a cricket ground built in 1883 in New Delhi is the second oldest international cricket stadium still functional in India, after the Eden Gardens in Kolkata. It also holds the record of the smallest cricket stadium in the world by boundary.

Spouse means a person's partner in marriage, it can be male or female.
But given F is spouse of B
And P is Son in law of N
Relation between F and B
Relation between P and A only
and p is male So, A must be female
=> B is male child.

The answer is 'mare' because a "mare’s nest" doesn't exist just like "hen's teeth" don't exist.

Hardness can be removed by adding sodium carbonate (washing soda) or by passing the water through an ion-exchange column.

Hardness in water is caused by dissolved magnesium ions and calcium ions. These can get into the water when it comes into contact with limestone and other rocks that contain calcium compounds. This can happen, for example, when rainwater flows over these rocks on its way to a reservoir.

Hardness in water is of two types. They are :

1. Temporary hardness

2. Permanent hardness

1. Temporary hardness:: Temporary hardness is caused by dissolved calcium hydrogen carbonate.

2. Permanent hardness:: Permanent hardness is caused by dissolved calcium sulfate. Unlike temporary hardness, it is not removed by boiling the water.

ASSISTANT→AAINSSSTT

STATISTICS→ACIISSSTTT

Here N and C are not common and same letters can be A, I, S, T. Therefore

 Probability of choosing A =  2C19C1×1C110C1 = 1/45 

 Probability of choosing I = 19C1×2C110C1 = 1/45

Probability of choosing S = 3C19C1×3C110C1 = 1/10

Probability of choosing T = 2C19C1×3C110C1 = 1/15

Hence, Required probability =   145+145+110+115= 1990