The number of solutions of the equation logx2x2+40log4xx-14log16xx3=0 is:
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If log330 = 1a and log530=1b then the value of 3log302 is:
The greatest possible value of n could be 9n < 108 if, given that log 3 = 0.4771 and n∈N:
Taking Log to both sides
we get
n = 8
Find x if
log1218 = log24x + 1. log24x+1 + 4
By trial and error method, when we substitute
x = 0
Both LHS and RHS are equal.
The value of x satisfying the following relation:
log12x = log23x-2
But at x=-1/3, log x is not defined.
The only admissible value of x is 1.
If A = log321875 and B = log2432187, then which one of the following is correct?
Given A = log321875 and B = log2432187
B = log352187 = log321875
=> A
Therefore, A = B
If a, b, c be the pth, qth and rth terms of a GP then the value of (q-r) log a + (r-p) log b + (p-q) log c is :
Find the logarithm of 144 to the base 23 :
log23144 = 4