AIEEE Questions

---

"G is father in law of D"
G+H means G is father of H
H is either son or daughter of G
H-R means H is sister of R
R@D means R is wife of D
so H and R are sisters
and daughters of G
so husband of R i.e. D is son in law of G
or G is father in law of D

As clear from the figure itself, triangle OQX and triangle O'PX are similar.

So,

OQ/O'P = OX/O'X

=> OX = (7/9)xO'X

And since, OX + O'X = 20

=> (7/9)xO'X + O'X = 20

=> O'X = 45/4

Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs

Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.

A bud is an undeveloped or embryonic shoot and may be specialized to develop flowers. Similarly, Seed is undeveloped and may be developed into a plant.

Hence, Flower : Bud :: Plant : Seed.

Let number of days Charan can do the same work alone is 'd' days.

According to the given data,

$$\begin{gathered} 512 + 716 + 14d = 1 \\ 14d = 1 - 20 + 2148 \\ 14d = 48 - 4148 \\ d = 14 x 487 \\ d = 96 days \end{gathered}$$

Therefore, Charan alone can complete the work in 96 days.

For the input "A rolling stone gathers no moss", the steps followed are:

Step 1: rolling A stone gathers no moss

Step 2: rolling stone A gathers no moss

Step 3: rolling stone gathers A no moss

Step 4: rolling stone gathers no A moss

After 4 steps the fifth word is "A".

If 'k' is number of students in P and 'l' is number of students in Q, then
From the given conditions, we have
=> k - 10 = l + 10 .......(1)
=> k + 20 = 2(l - 20) ....(2)

Solving these eqns, we get
k = 100 and l = 80.
Therefore, number of students in class Q is 80.

$$\begin{gathered} 75x321415 ÷ 525100 \\ 94 ÷ 525100 \\ 9002100 \\ = 37 \end{gathered}$$