AIEEE Questions

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By replacing the “?” with “x”

(12.5×14÷8.75) x (100/100) + 42 = 50 + X

(125*140)/875 + 42 = 50 + X

140/7 + 42 = 50 + X

20 + 42 = 50 + X

62 = 50 + X

X = 62 - 50

X = 12

Given Number series is :

3   4   14   48   576   27648

It follows a pattern that,

3

4

4 x 3 = 12   but not 14

12 x 4 = 48

48 x 12 = 576

576 x 48 = 27648

Hence, the odd one in the given Number Series is 14.

Clearly, the numerators of the fractions in the given sequence follow the series of 2, 3, 5, 7,... and the denominator follows 3, 9, 27, 81, 243, ...
Then, the next term in the given sequence is  935 = 9243 = 127 .

The given number series is 120, 36, 6, 2, 1, 1

120

120/5 = 24 (not 36)

24/4 = 6

6/3 = 2

2/2 = 1

1/1 = 1

Hence, the odd man in the given number series is 24.

In the figure, there are

5 columns containing 4 cubes each;

33 columns containing 3 cubes each;

9 columns containing 2 cubes each and 3 columns containing 1 cube each.

∴ Total Number of cubes = ( 5 x 4) + (33 x 3) + (9 x 2) + (3 x 1) = 20 + 99 + 18 + 3 = 140

534.596 + 61.472 – 496.708 = ? + 27.271

596.068 – 496.708 = ? + 27.271

? = 99.36 – 27.271

? = 72.089.

If the period between the two months is divisible by 7, then that two months will have the same calender .

 
(a). Oct + Nov  = 31 + 30 = 61 (not divisible by 7)

(b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31  = 214 (not divisible by 7)

(c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)

(d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)

Hence, April and July months will have the same calendar.

The given puzzle follows a logic that,

2 + 10 = 24 => 2 + 10 = 12 x 2 = 24

3 + 6 = 27 => 3 + 6 = 9 x 3 = 27

7 + 2 = 63 = 7 + 2 = 9 x 7 = 63

Similarly, 5 + 3 = 40 => 5 + 3 = 8 x 5 = 40.