AIEEE Questions

Q:

Find the missing number in the given number series?

1 8 36 ? 1100 7701

A) 97 B) 129
C) 164 D) 183
 
Answer & Explanation Answer: D) 183

Explanation:

The given number series is 1 8 36 ? 1100 7701

It follows a pattern that,

 

1

1 x 3 + 5 = 8

8 x 4 + 4 = 36

36 x 5 + 3 = 183

183 x 6 + 2 = 1100

1100 x 7 + 1 = 7701

 

Hence, the missing number in the given series is 183.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

13 28215
Q:

Which figure completes the series?

 

Question Figures ::                    Answer Figures ::

101558010123.png image

   A      B      C       D          E            1     2      3        4       5

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:

The pattern followed in the given figures is

 

 

 

One, two, three, one, two, three.....arcs get inverted sequentially. This inversion takes place in an Anti Clock Wise direction.

 

 

 

 

 

 

 

Hence, figure 1) will come in the next to complete the series.

Report Error

View Answer Report Error Discuss

Filed Under: Pattern Completion
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

19 28130
Q:

Find the next number in the given series?

118, 166, 190, 202, 208, ?

A) 211 B) 222
C) 233 D) 244
 
Answer & Explanation Answer: A) 211

Explanation:

The given series is 118, 166, 190, 202, 208, ?

118

118 + 48 = 166

166 + 24 = 190

190 + 12 = 202

202 + 6 = 208

208 + 3 = 211

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

11 28129
Q:

Brightness of bulb depends on voltage or current?

A) Current B) Voltage
C) Both A & B D) None
 
Answer & Explanation Answer: C) Both A & B

Explanation:

Brightness of bulb depends on both voltage and current. The brightness depends on power.

Since we know that  Power (P) = Voltage x Current = V I

So whether you increase the current or the voltage the brightness will increase.

 

Example Illustration:

 If you connect a long bulb and a round bulb in series, the long bulb glows but the round bulb does not. Both of them have the same current flowing through them (they are in series) but the long bulb has a greater voltage across it because it has more resistance (even though V= IR is not obeyed exactly, voltage drop does depend on the resistance). If you connect a round bulb and a long bulb in parallel, however, it is the round bulb that is brighter because now the voltage across both bulbs is the same but the current is larger through the round bulb (smaller resistance).

 

Hence, the brightness of a bulb depends on power i.e, both voltage and current.

Report Error

View Answer Report Error Discuss

Filed Under: Physics
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

31 28113
Q:

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red.

A) 23/42 B) 19/42
C) 7/32 D) 16/39
 
Answer & Explanation Answer: B) 19/42

Explanation:

A red ball can be drawn in two mutually exclusive ways

 (i) Selecting bag I and then drawing a red ball from it.

 

(ii) Selecting bag II and then drawing a red ball from it.

 

Let E1, E2 and A denote the events defined as follows:

E1 = selecting bag I,

E2 = selecting bag II

A = drawing a red ball

Since one of the two bags is selected randomly, therefore 

P(E1) = 1/2  and  P(E2) = 1/2

Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7

  PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6

 Using the law of total probability, we have 

 P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 

 

                          = 12×47+12×26=1942

Report Error

View Answer Report Error Discuss

Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

64 28028
Q:

If goods be purchased for Rs.450 and 1/3 is sold at a loss of 10%. At what gain % should the remainder is sold to has to gain 20% on the whole transaction?

A) 35% B) 28%
C) 22% D) 19%
 
Answer & Explanation Answer: A) 35%

Explanation:

Given the cost price of the articles = Rs. 450

To get overall 20% gain,

Total Selling Price = (20/100) x 450 = 540


One third of the CP = 1/3 x 450 = Rs. 150

But given 1/3 of articles are sold at 10% loss

S.P of 1/3 of articles = 90% of 150

= 90 x 150/100 = 135

 

Then, S.P on remaining 2/3 goods must be

= 450 - 135 = 405 ...........(1)

CP on remaining goods

= 2/3 x 450 = 300 ............(2)


Profit = SP - CP = 405 - 300 = 105


Profit %  = (105/300) x 100

= 35%.

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

45 27995
Q:

The First Mechanical Computer Designed by Charles Babbage was called?

A) Super Computer B) Abacus
C) Calculator D) Analytical Engine
 
Answer & Explanation Answer: D) Analytical Engine

Explanation:

Computer was invented by Charles Babbage.

The First Mechanical Computer Designed by Charles Babbage, a British mathematician was called as Analytical Engine which resembles today's modern machines  between 1833 and 1871.

Report Error

View Answer Report Error Discuss

145 27943
Q:

In a queue, Amrita is 10th from the front while Mukul is 25th from behind and Mamta is just in the middle of the two. If there be 50 persons in the queue. What position does Mamta occupy from the front ?

A) 14th B) 16th
C) 18th D) 20th
 
Answer & Explanation Answer: C) 18th

Explanation:

Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.

Report Error

View Answer Report Error Discuss

102 27875