Bank Exams Questions

---

Size of the primary memory of a PC ranges between 256 KB to 640 KB.

Brother of person's wife → brother-in-law of the person. Hence, the son of lady's brother is brother-in-law of the person.

Therefore, the brother of the lady is the father-in-law of the person. Hence, the lady is the sister of the person's father-in-law.

Let the principal amount be Rs. x
Calculating SI:
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 years it will be Rs (36/100)*x ------ (1)
Calculating CI:
For 1st year, Interest = (12/100)*x
For 2nd year, interest = (12/100)*x + (12/100)*x + (144/10000)*x
For 3rd year, interest = (12/100)*x + (12/100)*x + (12/100)*x + (144/10000)*x + (144/10000)*x + (1728/1000000)*x. ------ (2)
Subtracting equation 2 and 1 and solving further,
312*144*x/1000000 = 112.32
X = Rs 2500.
Alternative way: Using formula for Difference
between CI and SI for 3 years

we can also use the above formula to find the value of P.

I = (P x r x t)/100

I = $360

A = P+I

A = 2360

Let initially milk and water in container B is 3x liter and x liter respectively

Now, 3x + (8/9) × 18 – x – (1/9) × 18 = 30

3x + 16 – x – 2 = 30

x = 8

Initial quantity is container B = 8 (3 + 1) = 32 Liter.

Sound is a mechanical vibration and needs a medium for propagation. The higher the density of the medium, the faster the sound travels. So, sound cannot travel through vacuum.

As the sound travels faster in solids than liquids and gases, sound travels faster in the glass than Air and water.

The number of bonds between a pair of atoms is called the bond order.

Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two.

When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other.

In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O₂ molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.