Bank Exams Questions

---

The order of basicity for primary, secondary and tertiary amines are:

Secondary > Primary > Tertiary > NH3

* Amines are basic in nature as they have lone pair of electrons on nitrogen. Therefore, they have a strong tendency to donate this lone pair of electrons to electron acceptors.

* The stability of conjugate acids formed is dependent on the extent of H-bonding,and greater the number of H-atoms on N more stable is the conjugate acid.

* The conjugate acid of primary amine is the most stable with greater number (3) of H-bonds than > Secondary > tertiary. But primary amines are less basic than secondary as the electron density on the N atom is less and lone pair of electrons are not readily available for protonation.

* The two opposing factors i.e. the stability of conjugate acids formed and ease of availability of electrons for Protonation, balance each other in case of secondary amines and it is most basic.

South African Chris Bertish has become the first person to cross the Atlantic Ocean on standup paddle. He made the epic 4,050-mile voyage alone at sea aboard his custom-built craft.

Prahaar is a contemporary weapon system capable of carrying multiple types of warheads & neutralizing a wide variety of targets. It is a indigenously developed surface-to-surface tactical missile by DRDO.

Hypnology is the study of sleep.

Proteins are long chains of Amino acids. That is in brief, Amino acids are the monomers of Proteins. Amino acids are compounds which contain both an amino group and a carboxylic group. Proteins are made up of 20 essential amino acids.

Monomer means a small molecule of an organic substance i.e, building block in general.

Fouaad Mirza is related to the game Equestrian. His show wins first medal to India in equestrian game. He clinched silver medal in the individual event of equestrian game in the Asian games 2018. 

Fouaad Mirza belongs to Bangaluru.

1st copper wire: R = pl/A = pl/ πr2

2ndcopper wire: R’ = p’l’/A’ = pl/(4 πr2) = R/4

If joined in parallel, (1/Req) = (1/R) + (1/R’)

= 1/R + 4/R1/Req= 5/R

Req= R/5