(51 + 52 + 53 + .........+100) is equal to
51 + 52 + 53 + ...........+ 100
= (1 + 2 + 3 + .... + 100) - (1 + 2 + 3 + ...... + 50)
= It is in the form of n(n+1)2 series summation
= n1 = 100 , n2 = 50
=100100+12 - 5050+12
= (5050 - 1275) = 3775
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$M@A#N2B4O&3C5P+D2
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