4000+ Latest Bank Exams Questions and Answers with Explanation

Q:

In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ?

A) Quarter months	B) Half year
C) 2 years	D) 1 year

Answer & Explanation Answer: B) Half year

Explanation:

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

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Filed Under: Compound Interest
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Q:

A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ?

A) 85 km/hr	B) 95 km/hr
C) 105 km/hr	D) 120 km/hr

Answer & Explanation Answer: D) 120 km/hr

Explanation:

Initial speed = 80km/hr
Total distance = 80 x 10 = 800km
New speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

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Filed Under: Time and Distance
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Q:

Trans-Himalaya rivers are: _____________.

A) Sutlej, Indus, Gang	B) Brahmaputra, Indus, Sutlej
C) Brahmaputra, Indus, Ganga	D) Brahmaputra, Sutlej, Ganga

Answer & Explanation Answer: C) Brahmaputra, Indus, Ganga

Explanation:

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Filed Under: Indian Geography
Exam Prep: Bank Exams

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Q:

The following equation is incorrect. Which two signs should be interchanged to correct the equation?

12 ÷ 4 - 15 x 10 + 2 = 8

A) + and ÷	B) - and +
C) + and x	D) ÷ and x

Answer & Explanation Answer: C) + and x

Explanation:

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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

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Q:

In October 2017, RBI fixed the cash loading limit per month to ______ for Prepaid Payment Instruments.

A) Rs 10,000	B) Rs 50,000
C) Rs 75,000	D) Rs 1,00,000

Answer & Explanation Answer: B) Rs 50,000

Explanation:

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Filed Under: Indian Economy
Exam Prep: Bank Exams

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Q:

Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ?

A) Rs. 1,24,000	B) Rs. 1,44,000
C) Rs. 1,32,000	D) Rs. 1,62,000

Answer & Explanation Answer: B) Rs. 1,44,000

Explanation:

Value of Maruti Van, V1 = Rs. 1,96,000
Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 years
Let V2 is the value after depreciation.

$V 2 = V 1 {(1 - (\frac{r}{100}))}^{t}$
V2 = $19600 {[1 - (\frac{\frac{100}{7}}{100})]}^{2}$

V2 = 196000(6/7)(6/7)

V2 = (196000x36)/49 = Rs. 1,44,000.

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Filed Under: Percentage
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Q:

A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ?

A) 14.69 cm	B) 29.39 cm
C) 18.65 cm	D) 22.21 cm

Answer & Explanation Answer: B) 29.39 cm

Explanation:

Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.

As speed is same, area of cross sections should be same.

Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12

i.e ${πR}^{2} = 6 πR 1^{2}$

Here R = R and R1 = 12/2 = 6

$\Rightarrow R^{2} = 6 \times 6 \times 6$

R = 14.696

=> D = X = 14.696 * 2 = 29.3938 cm.

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Filed Under: Volume and Surface Area
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Q:

The more you take, the more you leave behind. What is that?

A) Pictures	B) Hole
C) Clothes	D) Footsteps

Answer & Explanation Answer: D) Footsteps

Explanation:

Yes, footsteps are what we take more, the more we leave behind.

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Filed Under: Logic Puzzles
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