A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ?
5/9 of the part of the population in a village are females. If 30 % of the females are married. The percentage of unmarried males in the total males is ?
Let total population = p number of females = 5p/9 number of males =(p-5p/9) = 4p/9 married females = 30% of 5p/9 = 30x5p/100x9 = p/6 married males = p/6 unmarried males =(4p/9-p/6) = 5p/18 Percentage of unmarried males in the total males = {(5p/18)/4p/9}x100 = (5p/18)x(9/4p) = 125/2 % = 62.5%
To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51).