Bank Exams Questions

Q:

A man goes down stream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the strean are 10km/hr and 14km/hr respectively, the distance of the destination from the string place is 

A) 16 km B) 18 km
C) 21 km D) 25 km
 
Answer & Explanation Answer: C) 21 km

Explanation:

Let the distance covered be D km. 

 D10+4+ D10-4 = 5

 D14+D6=5

 10D = 42 x 5 = 210

 

=> D = 21 km

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

32 10206
Q:

An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item?

A) Rs. 90 B) Rs. 75
C) Rs. 55 D) Rs. 40
 
Answer & Explanation Answer: D) Rs. 40

Explanation:

Let the cost price of the item = Rs. 50

Sold at 10% loss => for Rs. 50 loss  S.P = Rs. 45

From the  given data,

25/2 % gain if it is sold at Rs. 9 more

56.25 - 45 = 9

=> 11.25 = 9

=> 22.5 = 18

=> 45 = 36

=> 50 = ?

=> C.P = 50 x 3645 = 40

 

Hence, the Cost price of the item = Rs. 40.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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15 10204
Q:

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

A) .I only B) III only
C) I or II D) II and Either I or III only
 
Answer & Explanation Answer: D) II and Either I or III only

Explanation:

   I. gives, Rate = 5% p.a.

 

 II. gives, S.I. for 1 year = Rs. 600.

 

III. gives, sum = 10 x (S.I. for 2 years).

 


 Now I, and II give the sum.


 For this sum, C.I. and hence amount can be obtained.


 Thus, III is redundant.


 Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.


 Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.


Thus,Rate =100*12002*12000 =5%


Thus, C.I. for 2 years and therefore, amount can be obtained.


Thus, I is redundant.



Hence, I or III redundan
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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

5 10187
Q:

The bar graph represents the favourite fruit of grade 4 students.

 

Which fruit among the given below was chosen by the least students?

 

 

A) Mango B) Grapes
C) Orange D) Apple
 
Answer & Explanation Answer: B) Grapes

Explanation:
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Filed Under: Bar Charts
Exam Prep: Bank Exams

0 10184
Q:

In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends?

A) 240 B) 72
C) 48 D) 36
 
Answer & Explanation Answer: C) 48

Explanation:

DESIGN = 6 letters

 

No consonants appear at either of the two ends. 

2 x 4P4 =  2 x 4 x 3 x 2 x 1=  48

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
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10 10171
Q:

If you deposit $8000 into an account paying 7% annual interest compounded quarterly, how long until there is $12400 in the account?

A) 2.3 B) 3.3
C) 4.3 D) 6.3
 
Answer & Explanation Answer: D) 6.3

Explanation:

 

 

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

7 10167
Q:

The probability that z lies between 0 and 3.01

A) 0.4987 B) 0.5
C) 0.9987 D) 0.1217
 
Answer & Explanation Answer: A) 0.4987

Explanation:

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have

P(z<0) = 0.5

P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT
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37 10158
Q:

Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ?

A) 32 years B) 48 years
C) 62 years D) 50 years
 
Answer & Explanation Answer: D) 50 years

Explanation:

Let Rajan's present age be 'x' years.
=> Then his daughter's present age is = x/3 years.
His mother's present age = 13x/9 years
Now, according to the question,
x + x/3 + 13x/9 = 125
=> x = 125x9/25 = 45
Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9
=> 10 x 45/9 = 50 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

10 10156