Bank Exams Questions

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From the given information :

D O W N A M E == 5 @ 9 # 6 % 3
MODE = %@53

Longest and shortest phases Of cell cycle:

Shortest Phase - M phase or Mitotic phase.

Longest phase - G1 phase of the Interphase

Longest and shortest phases During Mitosis:

Longest Phase - Prophase

Shortest Phase - Anaphase

CP of 1000gm = Rs. 10
SP of 800gm = Rs. 12
SP of 1000gm =12x1000/800 = Rs. 15

Now take 1000gm as reference to calculate profit.
Profit=SP-CP=15-10=Rs. 5
Profit % = 5x100/10 = 50%

Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7

We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7

Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9

Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.

=> 60x5 : 36x6 : 75x3

=> 100 : 72 : 75

=> 72/247 x 7410 = Rs. 2160