4000+ Latest Bank Exams Questions and Answers with Explanation

Q:

Fastest Shorthand Writer was

A) Dr. G. D. Bist	B) J.R.D. Tata
C) J.M. Tagore	D) Khudada Khan

Answer & Explanation Answer: A) Dr. G. D. Bist

Explanation:

Dr. G. D. Bist, Guinness Record Holder, the first-ever Ph.D. in Stenography in the world.

fastest_shorthand_writer_-_Dr._G_._D_._Bist_1562583195.jpg image

He had achieved a highest speed of 250 w.p.m. in Shorthand.

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Q:

Simplify the following :

$\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$ ?

A) 100	B) 1
C) 4	D) 0

Answer & Explanation Answer: A) 100

Explanation:

Given $\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$

It is in the form of

$\frac{a^{3} + b^{3} + c^{3} - 3 a b c}{a^{2} + b^{2} + c^{2} - a b - b c - c a}$ = a + b + c

Here a = 37, b = 35 & c = 28

=> a + b + c = 37 + 35 + 28 = 100

Therefore, $\frac{(37)^{3}+(35)^{3}+(28)^{3}-3x37x35x28}{(37)^{2}+(35)^{2}+(28)^{2}-37x35-35x28-37x28}$ = 100

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19 65153

Q:

Find the angle between the hour hand and the minute hand of a clock when the time is 3.25

A) 47.5 degrees	B) 57.5 degrees
C) 45.5 degrees	D) 55.5 degrees

Answer & Explanation Answer: A) 47.5 degrees

Explanation:

At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins.

Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = (25 x 30) / 60 = 12.5°

Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°

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Q:

The compounded ratio of (2 : 3), (6: 11) and (11 :2) is

A) 1:2	B) 2:1
C) 11:24	D) 36:121

Answer & Explanation Answer: B) 2:1

Explanation:

Compounded Ratio :: When we compound two or more ratio's with each other through product or multiplication, the result is simply a compound ratio.

Thus, the product of two or more ratios; i.e, ab:cd is a ratio compounded of the simple ratios a:c and b:d.

Required compounded ratio = (2/3 x 6/11 x 11/2) = 2/1.

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Q:

________ is the process of dividing the disk into tracks and sectors

A) Tracking	B) Formatting
C) Crashing	D) Allotting

Answer & Explanation Answer: B) Formatting

Explanation:

The process of dividing the disk into tracks and sectors is called as formatting.

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Q:

Find the odd number out of the following number series?

2 4 8 11.5 18.25 28.375

A) 18.25	B) 28.375
C) 11.5	D) 8

Answer & Explanation Answer: D) 8

Explanation:

Given number series follows a pattern that,

2

2 x 1.5 + 1 = 4

4 x 1.5 + 1 = 7 (not equal to 8)

7 x 1.5 + 1 = 11.5

11.5 x 1.5 + 1 = 18.25

18.25 x 1.5 + 1 = 28.375

Hence, the odd number in the given number series is 8.

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Q:

A watch which gains uniformly ,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec.fast at 8 p.m on following sunday. when was it correct?

A) 7pm on wednesday	B) 20 min past 7pm on wednesday
C) 15min past 7pm on wednesday	D) 8pm on wednesday

Answer & Explanation Answer: B) 20 min past 7pm on wednesday

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains $5 + 5 \frac{48}{60}$ min in a time of (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

$\frac{54}{5} m i n \to 180 h o u r s$

5min ->

$(\frac{5}{\frac{54}{2}} \times 180)$

$83 \frac{1}{3} h r s = 72 h r s + 11 \frac{1}{3} h r s = 3 d a y s + 11 h r s + 20 m i n$

So the correct time will be shown on wednesday at 7:20 PM

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Q:

The blue colour of the clear sky is due to

A) Diffraction of light	B) Dispersion of light
C) Reflection of light	D) Refraction of light

Answer & Explanation Answer: B) Dispersion of light

Explanation:

A clear cloudless day-time sky is blue because molecules in the air dissipate blue light from the sun more than they dissipate red light. When we look towards the sun at sunset, we see red and orange hues on the grounds because the blue light has been scattered out and away from the line of sight.

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