Bank Exams Questions

Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

A) 85 B) 60
C) 55 D) 45
 
Answer & Explanation Answer: B) 60

Explanation:

Let M litres milk be added


=> 60 + M40 = 31


=> 60 + M = 120


=> M = 60 lit.

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Filed Under: Alligation or Mixture
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15 5862
Q:

When the price of rice decrease by 10%, a girl could buy 1 kg more for Rs. 270. Then, the original price of the rice per kg is

A) Rs. 36 B) Rs. 30
C) Rs. 28 D) Rs. 40
 
Answer & Explanation Answer: B) Rs. 30

Explanation:

From the given data,

When the price of rice is decreased by 10%, the value of Rs. 270 would become

270 x 100/90 = 300

Now, the value 270 becomes 300

And given, the girl could buy 1 kg extra for that value

Change in value = 300 - 270 = Rs. 30

 

Therefore, 1 kg extra rice she can get for Rs. 30

 

=> The original price of rice = Rs. 30/kg.

 

As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.  

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Filed Under: Percentage
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27 5861
Q:

Extensive planting of trees to increase forest cover is called

Extensive_planting_of_trees_to_increase_forest_cover_is_called1552993768.jpg image

A) Agroforestry B) Social forestry
C) Afforestation D) Deforestation
 
Answer & Explanation Answer: C) Afforestation

Explanation:

The process of extensive planting of trees or seeds in barren lands to increase forest cover is called as Afforestation.

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Filed Under: General Science
Exam Prep: AIEEE , Bank Exams , CAT
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4 5861
Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9 B) 605/9
C) 645/9 D) 700/9
 
Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

1.8x100 = 1.4

 

x = 1.4 × 1001.8 = 7009 = 77 79.

 

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8 5860
Q:

A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain?

A) 400 B) 376
C) 382 D) 356
 
Answer & Explanation Answer: A) 400

Explanation:

1st day the girl read = 40%

2nd day she read = 34 %

Remaining percentage of book = 100% - (40% +34%) = 26%

But given last two days she read equal number of pages

=> Each day she read 26%/2 = 13%

Last day she read 52 pages = 13%

13% = 52

1% = 4

=> 100% = 400

Total pages in the book is 400.

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Filed Under: Percentage
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12 5859
Q:

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:

A) 625 B) 635
C) 645 D) 655
 
Answer & Explanation Answer: A) 625

Explanation:

Let the sum be Rs. x. Then

C.I=x[1+4/100)^2-x]=[626/675x-x]

S.I=x^2/25

C.I-S.I=1

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Filed Under: Compound Interest
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0 5856
Q:

Unlike Mitosis, Meiosis results in the formation of

A) 2N daughter cells B) Haploid cells
C) body cells D) Diploid cells
 
Answer & Explanation Answer: B) Haploid cells

Explanation:

Unlike Mitosis, Meiosis results in the formation of 4 Genetically different cells.

 

Meiosis results in the formation of 4 Haploid daughter cells from one Diploid parent cell.

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Filed Under: Biology
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6 5850
Q:

A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately?

A) 20 B) 19
C) 17 D) 22
 
Answer & Explanation Answer: A) 20

Explanation:

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

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Filed Under: Volume and Surface Area
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