Bank Exams Questions

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Rate of rice of quantity 280 kg = Rs. 15.60/kg

Rate of rice of quantity 120 kg = Rs. 14.40/kg

He want to earn a profit of Rs. 10.45/kg

Rate of Mix to sell to get profit of 10.45 =  

$$\begin{gathered} 280 x 15.60 + 120 x 14.40280 + 120 + 10.45 \\ 4368 + 1728400 + 10.45 \\ => 15.24 + 10.45 \\ = 25.69 \end{gathered}$$

The One-word substitute for 'a post without remuneration' is Honorary.

Given two lines are parallel

pa+b=2

b=-pa+2..........(1)

3a+b=4

b=-3a+4 ...........(2)

m₁ = -p

m₂= -3

The condition for the two lines to be parallel is m₁=m₂

p = 3

The Jigme Dorji National Park is the second-largest National Park of Bhutan. The park provides sanctuary for 37 known species of mammals including several endangered, threatened or vulnerable species, such as the takin, snow leopard, clouded leopard, Bengal tiger, bharal or Himalayan blue sheep, etc. It is also home to the Indian leopard, serow, sambar, barking deer, goral, marmot, pika and more than 300 species of birds. It is also the only park in Bhutan where the national animal (takin), flower (blue poppy), bird (raven) and tree (cypress) exist together.

Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC
perpendicular to both chords. That divides the two chords in half.
So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.
We are given that BC = 5, the distance between the two chords. Let
OB = x.

We use the Pythagorean theorem on right triangle ABO

AO² = AB² + OB²
r² = 14² + x²

We use the Pythagorean theorem on right triangle DCO

DO² = CD² + OC²

We see that OC = OB+BC = x+5, so

r² = 10² + (x+5)²

So we have a system of two equations:

r² = 14² + x²
r² = 10² + (x+5)²

Since both left sides equal r², set the right sides
equal to each other.

14² + x² = 10² + (x+5)²
196 + x² = 100 + x² + 10x + 25
196 = 125 + 10x
71 = 10x
7.1 = x

r² = 14² + x²
r² = 196 + (7.1)²
r² = 196 + 50.41
r² = 246.41
r = √246.41
r = 15.69745202 cm

Given 10 men take 15 days to complete a work

=> Total mandays = 15 x 10 = 150

Let the work be 150 mandays.

=> Now 37 men can do 150 mandays in 150/37 =~ 4 days

Given letters are k, l, m, n, o = 5

number of letters to be in the words = 3

Total number of words that can be formed from these 5 letters taken 3 at a time without repetation of letters = 5P3 ways.

⇒ 5P3 = 5 x 4 x 3 = 60 words.