Bank Exams Questions

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Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.

We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.

The total selling price of the first and second article = 1.22C1 + 0.92C2.

As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.

Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

The absence of a nucleus is an adaptation of the red blood cell for its role. It allows the red bloodcell to contain more haemoglobin and, therefore, carry more oxygen moleculesLike red cells, platelets (thrombocytes) have no nucleus.Monocytes have a small spherical nucleus and has abundant dark staining condensed chromatin.There are 5 organelles found in a root hair cell. They are the: nucleus, cytoplasm, cell membrane, cell wall and vacuole.

Here in the above puzzle,

Consider the columns.

Column 1 = Row 1 + Row 2 = Row 3

That is,

44 + 12 = 56

Similarly,

48 + 30 = 78

Hence, 14 + 51 = 65.

Hence, the missing number in the given puzzle = 65.

Android 5.0 Lollipop is the first completely 64-bit compatible version of Android.

We know that Cubes with no surface painted can be find using x-23, where x is number of cuttings. Here x=6.

 ∴ 6-23=64

Relative speed = 60 + 90 = 150 km/hr.

= 150 x 5/18 = 125/3 m/sec.

Distance covered = 1.10 + 0.9 = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec.

Let the heights of Cat, Table and Turtle be C, T & R respectively.

From the above given figure,

C + T - R = 170 ......(a)

R + T - C = 130 ......(b)

Adding above eqns (a) & (b), we get

2T = 300

T = 150 cm

Hence, the height of the table is 150 cm.