Bank Exams Questions

Q:

Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage  Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is  ?

A) 30 B) 32
C) 38 D) None
 
Answer & Explanation Answer: C) 38

Explanation:

Let Raju's age at the time of his marriage = X years

Then from given data

=> X + 8 = 6/5 X

X = 40.

Since got married 8 years ago, his present age  = 48

His sister is 10 years younger => 48 - 10 = 38 years.

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Filed Under: Problems on Ages
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Q:

How many cubes of 10cm edge can be put in a cubical box of 1m edge

A) 10 B) 100
C) 1000 D) 10000
 
Answer & Explanation Answer: C) 1000

Explanation:

Number of cubes= (100x100x100) / (10x10x10)= 1000

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Filed Under: Volume and Surface Area
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45 15806
Q:

A cuboidal block 6cm x 9cm x 12cm is cut up into an exact number of equal cubes.The least possible number of equal cubes will be

A) 6 B) 9
C) 24 D) 30
 
Answer & Explanation Answer: C) 24

Explanation:

Volume of block=(6 x 9 x 12) cu.cm = 648 cu.cm 

Side of largest cube = H.C.F of 6,9,12 = 3cm 

Volume of the cube=(3 x 3 x 3)=27cu.cm 

Number of cubes=(648/27)=24

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Filed Under: Volume and Surface Area
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18 15758
Q:

The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

A) 12 B) 24
C) 36 D) 48
 
Answer & Explanation Answer: B) 24

Explanation:

side of first square = 40/4 =10cm

 

side of second square = 32/4 = 8cm

 

area of third squre = 10² - 8² = 36 sq cm

 

side of third square = 36 = 6 cm

 


required perimeter = 6*4 = 24cm

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Filed Under: Area
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8 15748
Q:

Ram and Raj start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Ram takes out Rs.1250 from his capital. After 1 more month, Raj takes out Rs.750 of his capital while Rakesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit ?

A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840 B) Ram - Rs. 900, Raj - Rs. 800, Rakesh - Rs. 840
C) Ram - Rs. 840, Raj - Rs. 920, Rakesh - Rs. 840 D) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 940
 
Answer & Explanation Answer: A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840

Explanation:

Initial investment of Ram = Rs.2500.
After 2 months he withdraw Rs.1250 from his capital.
Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months.

Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months.

And, Rakesh invested Rs.3500 for 3 months;

Their investing ratio:
Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)
= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42

Total profit for 6 months = Rs.2540
Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800
Raj's share = Rs.(2540 x 45/127) = Rs.900
Rakesh's share = Rs.(2540 x 42/127) = Rs.840

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Filed Under: Partnership
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8 15716
Q:

A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ?

A) Rs.37,500 B) Rs.36,400
C) Rs.37,415 D) Rs.36,500
 
Answer & Explanation Answer: A) Rs.37,500

Explanation:

Assume A be the cost price.

 

Therefore,
35×A×10100 - 25×A×5100 = 1500

 

=>  A = Rs 37,500.

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Filed Under: Profit and Loss
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28 15707
Q:

M and N have children A and B.
F is spouse of B.
D is child of F.
P is son in law of N.
K is kid of P.

Who is male chiled of M and N ?

A) B B) A
C) None D) Can't be determined
 
Answer & Explanation Answer: A) B

Explanation:

Spouse means a person's partner in marriage, it can be male or female.
But given F is spouse of B
And P is Son in law of N
Relation between F and B
Relation between P and A only
and p is male So, A must be female
=> B is male child.

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Filed Under: Logic
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14 15674
Q:

Pick an odd man in the given number series?

4 12 38 87 198

A) 12 B) 38
C) 87 D) 198
 
Answer & Explanation Answer: A) 12

Explanation:

The given series follows a pattern that,

 

4 + 32 = 4 + 9 = 1313 + 52 = 13 + 25 = 3838 + 72 = 38 + 49 = 8787 + 92 = 87 + 81 = 198 

 

Hence, the odd man in the given number series is 12.

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Filed Under: Odd Man Out
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