4000+ Latest Bank Exams Questions and Answers with Explanation

Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315	B) 385
C) 415	D) 485

Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $[x - (700 - x)] = \frac{1}{5} [\frac{x + (700 - x)}{2}]$

$\Rightarrow 2 x - 700 = 70$

$\Rightarrow x = 385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

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Filed Under: Area
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18 28136

Q:

Which of the following terms follows the trend of the given list?

XYZXYZxYZ, XYZXYzXYZ, XYZXyZXYZ, XYZxYZXYZ, XYzXYZXYZ, _______________.

A) xYZXYZXYZ	B) XYZXYZxYZ
C) XyZXYZXYZ	D) XYZXYzXYZ

Answer & Explanation Answer: C) XyZXYZXYZ

Explanation:

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Filed Under: Alphabet Test
Exam Prep: Bank Exams

1 28131

Q:

If the mathematical operator, '+' means 'x', '/' means '-', '-' means '+', and 'x' means '/', then the value of 11 +14 x7- 5 / 29 is

A) -5	B) -12
C) -7	D) -2

Answer & Explanation Answer: D) -2

Explanation:

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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

2 28129

Q:

The following equation is incorrect. Which two signs should be interchanged to correct the equation?

15 x 4 + 10 - 10 ÷ 14 = 10

A) - and +	B) + and ÷
C) ÷ and x	D) x and -

Answer & Explanation Answer: B) + and ÷

Explanation:

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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

0 28128

Q:

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red.

A) 23/42	B) 19/42
C) 7/32	D) 16/39

Answer & Explanation Answer: B) 19/42

Explanation:

A red ball can be drawn in two mutually exclusive ways

(i) Selecting bag I and then drawing a red ball from it.

(ii) Selecting bag II and then drawing a red ball from it.

Let E1, E2 and A denote the events defined as follows:

E1 = selecting bag I,

E2 = selecting bag II

A = drawing a red ball

Since one of the two bags is selected randomly, therefore

P(E1) = 1/2 and P(E2) = 1/2

Now, $P (\frac{A}{E_{1}})$ = Probability of drawing a red ball when the first bag has been selected = 4/7

$P (\frac{A}{E_{2}})$ = Probability of drawing a red ball when the second bag has been selected = 2/6

Using the law of total probability, we have

P(red ball) = P(A) = $P (E_{1}) \times P (\frac{A}{E_{1}}) + P (E_{2}) \times P (\frac{A}{E_{2}})$

= $\frac{1}{2} \times \frac{4}{7} + \frac{1}{2} \times \frac{2}{6} = \frac{19}{42}$

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Filed Under: Probability
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64 28105

Q:

The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter

A) Rs.16500	B) Rs.15500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: A) Rs.16500

Explanation:

l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

18 28099

Q:

The purpose of land reforms was to achieve ___________.

A) increase in production	B) increase the purchasing power of the rural population
C) ensure distributive justice with economic growth	D) All options are correct

Answer & Explanation Answer: D) All options are correct

Explanation:

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Filed Under: Indian Economy
Exam Prep: Bank Exams

1 28080

Q:

In the following question, select the missing number from the given series.

46, 41, 35, 30, ?, 19, 13

A) 26	B) 24
C) 28	D) 22

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