Sawaal

GATE Questions

Popular Latest Rated
Q:

X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After another 3 months, X withdrew two- sevenths of his stock but after 3 months, he puts back three-fifths of what he had withdrawn. The total profit at the end of the year is Rs. 726. How much of this should X receive?

A) Rs. 336 B) Rs. 366
C) Rs. 633 D) Rs. 663
 
Answer & Explanation Answer: B) Rs. 366

Explanation:

Profit ratio X & Y = (700 × 3) + (700 × 5/7× 3) + (700× 5/7 + 200 × 3/5 )× 6 : 600 ×12
X:Y= 7320 : 7200= 183:180
∴ X’s share from profit = 183 × 726/(183+180) = Rs. 366.

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

1 3804
Q:

Cost price of a pen is 50 Rs. and that of notebook is 140 Rs. If pen is sold at 200% profit, then to purchase 10 such note books how many pens are required to sell if only profit money is used to buy notebooks?

A) 14 B) 18
C) 15 D) 20
 
Answer & Explanation Answer: A) 14

Explanation:

C.P. of 10 note books ⇒ 140 × 10 = 1400 Rs.
Profit on selling one pen ⇒ 50×200/100 = Rs 100
Number of pen required ⇒ 1400/100 = 14

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 1344
Q:

Length of two trains are 150 m and 200 m respectively and the ratio (shorter: longer) of their speed is 2 : 5. If they cross each other in opposite direction in 15 second then in what time faster train will overtake the slower train.

A) 20 seconds B) 25 seconds
C) 32 seconds D) 35 seconds
 
Answer & Explanation Answer: D) 35 seconds

Explanation:

Let speed of slower train = 2x
⇒ speed of faster train = 5x
ATQ, (150 + 200)/(2x + 5x) = 15
x = 10/3
Time required=350/[50/3–20/3]= 35 seconds

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 1006
Q:

If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm2 less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.

A) 66 cm B) 88 cm
C) 80 cm D) 72 cm
 
Answer & Explanation Answer:

Explanation:

Let length and breadth of rectangle be L cm
and B cm respectively So, ATQ
Area1= (L-6)×B
But this is square, so L-6=B
Area1= (L-6) × (L-6)
Case 2, Area2= L × (B+6),
L=B+6
So, Area2= L × L,
Given, Area2-Area1= 252(L)2-(L-6)2=252
Solving this, L= 24
B= 18
Perimeter= 2(L+B)= 2(24+18)= 84 cm

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

1 1685
Q:

Breadth of a rectangle is equal to the diagonal of the square whose side is 2.5√2 cm. Ratio between length and breadth of rectangle is 3 : 1. Find the area of the rectangle (in cm2).

A) 75 B) 90
C) 85 D) 80
 
Answer & Explanation Answer: A) 75

Explanation:

Diagonal of Square = Side √2= 2.5√2 × √2= 5 cm
Breadth = 5 cm
Length of rectangle = 5 × 3 = 15 cm
Area of rectangle = 15 × 5 = 75 cm2

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 967
Q:

Equal distance is covered by a boat in upstream and in downstream in total 5 hours. Sum of speed of a boat in upstream and downstream is 40 km/hr. Speed of boat in still water is 600%
more than the speed of stream. Find theapproximate distance covered by boat in downstream (in km).

A) 45 B) 50
C) 55 D) 60
 
Answer & Explanation Answer: B) 50

Explanation:

let speed of boat= X, speed of stream= Y
Upstream speed= X-Y
Downstream speed= X+Y
Sum of upstream & downstream= (X-Y) +(X+Y)= 2X
So, 2X= 40
X= 20 km/hr
Speed of boat : speed of stream= 600+100 :100= 7:1
So speed of Stream= 20/7 km/hr
ATQ, D/( X-Y) + D/( X+Y) = 5
D/(120/7) + D/(160/7)= 5
D= 480×5/49= 48.97 km= 50 Km(approx)

Report Error

View Answer Report Error Discuss

Filed Under: Boats and Streams
Exam Prep: Bank Exams , GATE

9 3130
Q:

A and B entered into a partnership with Rs.800 and Rs.1600 respectively. From 9th months onward they each decided to invest Rs.100 more on starting of each month. If total annual profit is Rs.7700 then find the profit share of A.

A) Rs.2550 B) Rs.3200
C) Rs.2650 D) Rs.2450
 
Answer & Explanation Answer: C) Rs.2650

Explanation:

A : B = (800 × 8+ 900+ 1000+ 1100+ 1200): (1600 × 8+ 1700+ 1800+ 1900+ 2000)
A : B = 53 : 101
Profit of A ⇒ 7700 ×53/154 = 2650 Rs.

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 1669
Q:

A starts a business, after 6 months B also join him with Rs.4500 and after 2 months of B’s joining C also join them with Rs.4500. If A gets approx. Rs 4900 out of total annual profit of Rs. 10,000 then find the approximate value of initial investment of A.

A) Rs.4800 B) Rs.4200
C) Rs.3600 D) Rs.4400
 
Answer & Explanation Answer: C) Rs.3600

Explanation:

Let initial investment of A = x
Ratio of profit A : B : C = 12 × x : 6×4500 :4×4500
A :B:C = x : 2250: 1500
Now ATQx/(x+2250+1500) = 4900/10000
solving this we get,x ≈ Rs 3600

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

1 1587