GATE Questions

Q:

What is the main function of an ignition safety switch?

Answer

An ignition safety switch is a safety device can shut off the engine if the operator falls off the PWC or out of the powerboat, or is otherwise thrown from the proper operating position.


 


How it works:


It allows the engine of the vehicle to shut off or to be turned off immediately as it is to prevent further complications to happen as this is being used when an emergency is launched


 


Where it is used:


Most powerboats and PWCs come equipped by the manufacturer with an emergency engine cut-off switch.

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Subject: Physics Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 7508
Q:

A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current?

A) 5:1 B) 3:1
C) 4:1 D) 2:1
 
Answer & Explanation Answer: A) 5:1

Explanation:

Let the speed of the man in still water = p kmph

Speed of the current = s kmph

Now, according to the questions

(p + s) x 10 = (p - s) x 15

2p + 2s = 3p - 3s

=> p : s = 5 : 1

 

Hence, ratio of his speed to that of current = 5:1.

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Filed Under: Boats and Streams
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23 7504
Q:

There are 44 students in a hostel, due to the administration,  15 new students has joined. The expense of the mess increase by Rs. 33 per day. While the average expenditure per head diminished by Rs. 3, what was the original expenditure of the mess ?

A) Rs. 404 B) Rs. 514
C) Rs. 340 D) Rs. 616
 
Answer & Explanation Answer: D) Rs. 616

Explanation:

Let the average expenditure per head be Rs. p
Now, the expenditure of the mess for old students is Rs. 44p
After joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3
Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33
Therefore, 59(p-3) = 44p + 33
59p - 177 = 44p + 33
15p = 210
=> p = 14
Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

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Filed Under: Average
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11 7502
Q:

Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?

A) 79 B) 77
C) 76 D) 73
 
Answer & Explanation Answer: A) 79

Explanation:

Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 65.
i.e (58+58+x)/3 = 65
116 + x = 195
x = 79 marks.

Therefore, the maximum marks he can score in maths is 79.

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5 7489
Q:

Manoj and Satya are ranked seventh and eleventh respectively from the top in a class of 31 students. What will be their respective ranks from the bottom in the class ?

A) 25th and 21st B) 26th and 22nd
C) 20th and 24th D) 24th and 20th
 
Answer & Explanation Answer: A) 25th and 21st

Explanation:

Number of students behind Manoj in rank = (31 - 7) = 24.

So, Manoj is 25th from the bottom.

Number of students behind Satya in rank = (31 - 11) = 20.

So, Satya is 21st from the bottom.

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22 7488
Q:

Microphone : Loud :: Microscope : ?

A) Investigate B) Magnify
C) Examine D) Elongate
 
Answer & Explanation Answer: B) Magnify

Explanation:

As Microphone makes sound louder similarly Microscope makes the object magnified.

 

Hence, Microphone : Loud :: Microscope : Magnify.

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Filed Under: Analogy
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4 7487
Q:

What should come next in the following letter series based on English alphabet ?
CEA JLH QSO ?

A) WYU B) UXW
C) WXV D) XZV
 
Answer & Explanation Answer: D) XZV

Explanation:

In the given series, each letter moves seven letters forward to obtain the next.
So, XZV replaces ? in the series.

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Filed Under: Alphabet Test
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13 7486
Q:

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?

A) 6 B) 8
C) 4 D) 9
 
Answer & Explanation Answer: C) 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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17 7480