GATE Questions

Q:

Which type of molecule is CF4?

A) nonpolar, with a symmetrical distribution of charge B) polar, with an asymmetrical distribution of charge
C) nonpolar, with an asymmetrical distribution of charge D) polar, with a symmetrical distribution of charge
 
Answer & Explanation Answer: A) nonpolar, with a symmetrical distribution of charge

Explanation:

CF4 is tetrahedral.

Since the four 'F' atoms have the same electronegativity values, there is no bias in electron distribution toward any one.

 

Therefore, electron/charge distribution is symmetrical, which also means that the molecule is nonpolar.

 

Hence, CF4 is nonpolar molecule with a symmetrical distribution of charge.

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Filed Under: Chemistry
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3 5069
Q:

Vishal is 24th from either end of the row of boys ? How many boys are there in the row ?

A) 48 B) 49
C) 46 D) 47
 
Answer & Explanation Answer: D) 47

Explanation:

Given that Vishal is 24th from either end of the row i.e from two sides

  1 2 3 4 5 . . . . . .24 23 22 21 20 . . . . . 5 4 3 2 1 

  Here before Vishal there are 23 members and after Vishal there are 23 members

  = 23+1+23 --> 47 members in the row.

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Filed Under: Number, Ranking and Time Sequence Test
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13 5059
Q:

A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?

A) 6.24 sec B) 6.58 sec
C) 7.325 sec D) 7.65 sec
 
Answer & Explanation Answer: D) 7.65 sec

Explanation:

Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec

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8 5057
Q:

If the positions of the first and the fifth digits of the number 14278359 are interchanged, similarly the positions of the second and the sixth digits are interchanged and so on, then which of the following will be the second digit from the right end after the rearrangement ?

A) 5 B) 2
C) 7 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:

Given number is 14278359
As given 1st and 5th digits, 2nd & 6th, 3rd & 7th and 4th & 8th digits are to to be interchanged.
Therfore, the rearranged number is 83591427
Then, the second digit from the right end is 2.

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Filed Under: Arithmetical Reasoning
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8 5056
Q:

The sum of the digits of a two-digits number is 10,while when the digits are reversed, the number decreases by 54. Find the changed number ?

A) 28 B) 19
C) 37 D) 46
 
Answer & Explanation Answer: A) 28

Explanation:

Let the original number is 82 i.e 8 + 2 = 10 and when the digits are reversed i.e 28
The difference is 82 - 28 = 54 i.e, the number is decreased by 54.

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Filed Under: Numbers
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7 5056
Q:

What do you understand by - 'If K is there L has to be there'

A) K & L will always be together B) K is not there, then L will not be there
C) k is there, then L will also be there D) K & L will always be not together
 
Answer & Explanation Answer: C) k is there, then L will also be there

Explanation:

This would not mean that K and L will always be together. It just implies that, if K is there, then L will also be there.

At the same time, it can happen that L is there but K isn't.

Remember, the condition is on K, not on L.

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Filed Under: Analytical Reasoning
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17 5054
Q:

Iteration is most similar in meaning to

A) Looping B) Starting
C) Ending D) None of the above
 
Answer & Explanation Answer: A) Looping

Explanation:

Iteration means doing something again and again, repeatedly,... 

 

Hence, looping is a process of repeating a method and so it is similar in meaning to Iteration.

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Filed Under: English
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3 5054
Q:

If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ?

A) 75 min B) 82 min
C) 90 min D) 101 min
 
Answer & Explanation Answer: C) 90 min

Explanation:

Let X = Time taken for each of Type B Problems(100 Problems)
And 2X = Time taken for each of Type A problems(50 problems)

Total time period = 3hrs = 3 x 60min = 180 minutes

100X + 50(2X) = 180
100X + 100X = 180
200X = 180 min

X = 180/200
X = 0.90 min

By convertiing into seconds,

X = 0.90 x 60 seconds
X = 54 sec

So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds
= 5400/60sec = 90 minutes.

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Filed Under: Percentage
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8 5048