GATE Questions

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Let the present age of Raj and Rajitha be 4x and 9x.
Then, according to question,
9x = 2(9x-12)-3 => 9x = 27 => x = 3
Raj's present age = 4x = 12yrs,
After 5 years Raj's age will be 12 + 5 = 17 yrs.

Money lent to A+B = (300 + 540) = Rs. 840 

Amount received = Rs. 1032 

Interest received = Rs. 1032 - Rs.840 = Rs. 192

Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12 

Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36 

Total yearly interest = Rs.(12+36) = Rs.48 

If interest is Rs. 48, time = 1 year 

If interest is Rs. 192, time =  192/48 = 4 years 

Yes, all the given statements are NOT true about electrons and atomic orbitals.

True statements are ::

An orbital can contain a maximum of two electrons.

An atom’s lowest energy level has only one orbital.

An electron has different amount of energies in all orbitals.

Speed = 108 km/hr
enter a tunnel,, means that the train covers a distance equal to its own length
so (108 x 5/18) = x/4 where x= length of train
hence x = 120 mtrs
to pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.
so (1120/t) = (108x5/18)
t = 37.33 sec

ELISA - Enzyme-Linked Immuno Sorbent Assay.

An ELISA test may be used to diagnose: HIV, which causes AIDS.

An ELISA also called EIA, is a test that detects and measures antibodies in your blood. Antibodies are proteins that your body produces in response to harmful substances called antigens.

Let the price of 1 litre of diesel be Rs.x and let Karthik initially buy 'y' litres of diesel.
Therefore, he would have spent Rs. xy on diesel.

When the price of diesel increases by 25%, the new price per litre of diesel is 1.25x.

Karthik intends to increase the amount he spends on diesel by 15%.
i.e., he is willing to spend xy + 15% of xy = 1.15xy

Let the new quantity of diesel that he can get be 'q'.
Then, 1.25x x q = 1.15xy
Or q = (1.15/1.25)y = 0.92y.

As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier.

Or a reduction of 8%.

Given K=4L 

-->K+L = 4L+L = 5L

These 5L people can complete the work in 24 days, which means L alone can do the work in (24 x 5)=120 days.

Hence, K alone can do the work in 120/4= 30 days.

Let the Efficiency of pavan be E(P)

Let the Efficiency of sravan be E(S)

Here Work W = LCM(25,20) = 100

Now, E(P+2S) = 100/25 = 4 ....(1)

E(2P+S) = 100/20 = 5 ....(2)

Hence, from (1) & (2) we get

E(S) = 1

=> Number of days Savan alone work to complete the work  = 100/1 = 100 days.