GATE Questions

Q:

If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?

A) 14 kmph B) 13 kmph
C) 12 kmph D) 11 kmph
 
Answer & Explanation Answer: C) 12 kmph

Explanation:

The distance is constant in this case.

Let the time taken for travel with a speed of 10 kmph be 't'.

Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.

Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)

Extra time taken = t - 2t/3 = t/3

=> 1pm - 11am = 2hrs

=> t/3 = 2h

=> t = 6 hrs.

Now, Distance = speed x time = 10 x 6 = 60 kms

Time he takes to reach at noon = 6 - 1 = 5 hrs

Now, Speed = 60/5 = 12 kmph.

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Filed Under: Time and Distance
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12 5690
Q:

Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?

A) 10 kms B) 8 kms
C) 6 kms D) 4 kms
 
Answer & Explanation Answer: D) 4 kms

Explanation:

Let the actual distance be t kms

Now, According to the data,

 

5t + 860 = 6t=> 560t + 860 = 6t=> 60t + 8 = 72t=> 8 = 12t=> t = 8/12 = 2/3 hrs

 

Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.

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Filed Under: Time and Distance
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17 5688
Q:

That which cannot be seen -

A) Invisible B) Unseen
C) Intangible D) All of the above
 
Answer & Explanation Answer: A) Invisible

Explanation:
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Filed Under: English
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10 5687
Q:

Sponge is to Porous as Rubber is to

A) Inflexible B) Elastic
C) Solid D) Massive
 
Answer & Explanation Answer: B) Elastic

Explanation:

A sponge is a porous material. Rubber is an elastic material. 

Since Rubber is not a Massive or solid and not an inflexible thing, it is elastic. 

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Filed Under: Analogy
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3 5686
Q:

If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?

A) Rs. 175 B) Rs. 325
C) Rs. 340 D) Rs. 260
 
Answer & Explanation Answer: C) Rs. 340

Explanation:

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

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Filed Under: Chain Rule
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22 5669
Q:

What goes up when rain comes down?

A) Air B) Heat
C) Umbrella D) None
 
Answer & Explanation Answer: C) Umbrella

Explanation:

Yes, when rain starts falling umbrella goes up for pretecting us from wetting.

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Filed Under: Logic Puzzles
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7 5667
Q:

A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately?

A) 20 B) 19
C) 17 D) 22
 
Answer & Explanation Answer: A) 20

Explanation:

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

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Filed Under: Volume and Surface Area
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17 5667
Q:

Pavan and Sravan are two persons. If Pavan works with his actual efficiency and Sravan twice of his actual efficiency then it takes 25 days to complete the work. But If Pavan works twice of his actual efficiency and Sravan with his normal efficiency then the work is completed in 20 days. How many days would it take if Sravan alone works with his actual efficiency (in Days)?

A) 50 B) 100
C) 70 D) 35
 
Answer & Explanation Answer: B) 100

Explanation:

Let the Efficiency of pavan be E(P)

Let the Efficiency of sravan be E(S)

Here Work W = LCM(25,20) = 100

Now, E(P+2S) = 100/25 = 4 ....(1)

E(2P+S) = 100/20 = 5 ....(2)

Hence, from (1) & (2) we get

E(S) = 1

=> Number of days Savan alone work to complete the work  = 100/1 = 100 days.

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Filed Under: Time and Work
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