GATE Questions

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Total quantity of sugar = 45 + 30 = 75

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

= 11.25

Hence, in the overall transaction, Rishi got Rs. 11.25 gain.

Let the speed of the train be 'S' kmph

From the given data,

Distance = Length of train = D = 200 mts = 200 x 18/5 kms

Time = 10 sec

given speed of the motorcycler = 12 kmph

Relative speed as they are moving in the same direction = (S - 12) kmph

$$\begin{gathered} (S- 12) = 200 x 18515 \\ S - 12 = 48 \\ S = 60 kmph \\ \end{gathered}$$

Hence, the speed of the train = S = 60 kmph

Now,

Let the speed of the jeep be 'x' kmph

$$\begin{gathered} 60 - x = 200 x 18520 \\ 60 - x = 36 \\ x = 60 - 36 \\ x = 24 kmph \end{gathered}$$

Therefore, the speed of the jeep = x = 24 kmph.

India's largest cab aggregator Ola has partnered with Bharti Airtel to launch a range of integrated digital offerings to customers.

 As part of the partnership, Ola will integrate Airtel Payments bank to its app and Airtel will integrate Ola's mobile wallet Ola Money as a payment solution on Airtel website and MyAirtel app for mobile recharges and bill payments.

ST candidates vacancies can be filled by C35 ways = 10 

Remaining vacancies are 5 that are to be filled by 12 

=> C512= (12x11x10x9x8)/(5x4x3x2x1) = 792 

Total number of filling the vacancies = 10 x 792 = 7920

Literally any percentage means divide by 100.

So 125% = 125100. That can be reduced to 5/4.

To convert to a decimal, you can do long division, dividing 5 into 4.

Given A,B,C can complete a work in 15,20 and 30 respectively.

The total work is given by the LCM of 15, 20, 30 i.e, 60.

A's 1 day work = 60/15 = 4 units

B's 1 day work = 60/20 = 3 units

C's 1 day work = 60/30 = 2 units

(A + B + C) worked for 2 days = (4 + 3 + 2) 2 = 18 units

 Let B + C worked for x days = (3 + 2) x = 5x units

C worked for 2 days = 2 x 2 = 4 units

Then, 18 + 5x + 4 = 60

22 + 5x = 60

5x = 38

x = 7.6

Therefore, total number of days taken to complete the work = 2 + 7.6 + 2 = 11.6 = 11 3/5 days.

Let the number of days be 'p' 

As the work is same, we know that

M1 x D1 x H1 = M2 x D2 x H2

Where M = Men, D = Days, H = Hours per day 

Here M1 = 9, D1 = 15, H1 = 7 

M2 = 6, D2 = p, H2 = 9 

=> 9 x 15 x 7 = 6 x p x 9 

=> p = 35/2 = 17.5 days.

Let the monthly salary of Shankar be = Rs.x
Amount invested on expenditure = 25% = x/4;
Remaning amount = 3x/4;
Amount invested on children education = 20% i.e = 3x/20;
Remaining amount = 3x/4 - 3x/20 = 3x/5;
Remaining amount invested in three different schemes i.e is 1/3(3x/5)
=> x/5 = 5600
Therefore x = 28000
Hence, Monthly salary of Shankar is Rs. 28,000.