GATE Questions

---

The given inequality is 3p - 16 < 20

For solving this inequality, follow these steps

Now add 16 on both sides

we get 3p - 16 + 16 < 20 + 16

=> 3p  < 36

Now divide the above eqn with 3 on both sides

we get, 3p/3 < 36/3

p < 12.

Financial support to the tourism sector is not a permanent solution. Secondly, constant risk for the foreign tourists will never encourage tourism in India. Hence, none of the course action is the right solution in this direction.

The given statement is True.

Ketchup is acidic, having a pH of 3.9. The acidic component, acetic acid, will react with the metal tin. This reaction will result in a metal acetate that will contaminate the ketchup.

Hence, The acetic acid in the ketchup will react with the metal tin, forming a metal acetate that will pass into the ketchup which leads to its contamination.

The four bonds of carbon tetrachloride (CCl4) are polar, but the molecule is nonpolar because the bond polarity is cancelled by the symmetric tetrahedral shape. Hence, making the net dipole as zero and molecule as non-polar.

When other atoms substitute for some of the Cl atoms, the symmetry is broken and the molecule becomes polar.

Small means a little in size or quantity.

Here in the given options, Tiny means same as small.

Hence, Small most nearly means as Tiny.

The number of bonds between a pair of atoms is called the bond order.

Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two.

When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other.

In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O₂ molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

8(6+5) - 10 = ?

? = 8(11) - 10

? = 88 - 10

? = 78.