GATE Questions

Q:

A girl facing north rotates 100(degree) clockwise then 190(degree) anticlockwise. what is new direction of the girl ?

A) North-East B) West
C) South-East D) South
 
Answer & Explanation Answer: B) West

Explanation:

First girl facing North
Then she rotates 100 deg clock wise => 10 deg ES
Then again she rotates 190 deg anti clock wise => for 100 deg it is North and more 90 deg means West.
Therefore, the new direction of the girl is West.

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Filed Under: Direction Sense Test
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52 12502
Q:

One paper is equally folded 35 times, then what is the new thickness of the paper ?

A) T(2^50) B) 50T
C) 2 x 50 T D) T/50
 
Answer & Explanation Answer: A) T(2^50)

Explanation:

Let initial thickness of the paper be 'T'
after first fold it will be '2T' = 21T
after second fold it will be '4T' = 22T 
after 50th fold it will be T x (250T)

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Filed Under: Logic
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5 2781
Q:

A Cricket team of 23 people all shake hands with each other exactly once. How many hand shakes occur ?

A) 142 B) 175
C) 212 D) 253
 
Answer & Explanation Answer: D) 253

Explanation:

The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on...
So,
22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.

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Filed Under: Permutations and Combinations
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4 5128
Q:

A man sell 35 waffers for Rs. 15 each and loses Rs. 40.4. If he sells 35 waffers for Rs. 18, how much does he loss or gain ?

A) Rs. 64 B) Rs. 52
C) Rs. 72 D) Rs. 55
 
Answer & Explanation Answer: A) Rs. 64

Explanation:

Given Loss = Rs. 40.4
We know loss = cost price - selling price
40.4 = CP - 35(15)
=> CP = 40.4 + 525
=> CP = Rs. 565.4
Now the New selling price of waffer is Rs. 18
=> SP = 35(18) = 630
Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.

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Filed Under: Profit and Loss
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5 3044
Q:

In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ?

A) 18 B) 14
C) 22 D) 24
 
Answer & Explanation Answer: B) 14

Explanation:

1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14
Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between them
So minimum no. of boys standing in the queue = 14

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Filed Under: Chain Rule
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27 4327
Q:

There are 44 students in a hostel, due to the administration,  15 new students has joined. The expense of the mess increase by Rs. 33 per day. While the average expenditure per head diminished by Rs. 3, what was the original expenditure of the mess ?

A) Rs. 404 B) Rs. 514
C) Rs. 340 D) Rs. 616
 
Answer & Explanation Answer: D) Rs. 616

Explanation:

Let the average expenditure per head be Rs. p
Now, the expenditure of the mess for old students is Rs. 44p
After joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3
Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33
Therefore, 59(p-3) = 44p + 33
59p - 177 = 44p + 33
15p = 210
=> p = 14
Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

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11 7496
Q:

Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ?

A) 24 $ B) 22 $
C) 16 $ D) 14 $
 
Answer & Explanation Answer: C) 16 $

Explanation:

Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid 28×245790 = 16 $.

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Filed Under: Time and Work
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5 9294
Q:

Find the missing number in the given series ?

15, 51, 216, 1100, ?, 46452

A) 5660 B) 6560
C) 6750 D) 6630
 
Answer & Explanation Answer: D) 6630

Explanation:

Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get

15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452

Therefore, the missing number is 6630.

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Filed Under: Number Series
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48 27033