GATE Questions

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Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.

Since the narrator has no brother, his father’s son is he himself. So, the man who is talking is the father of the man in the photograph. Thus, the man in the photograph is his son.

Given that the next word should start with the ending two letters of the previous word. From this,

The first word is

SHIVER

Now, the next word should start with ER and must contain OT in the middle.

EROTIC

Now, the next word should start with IC and must contain IC in the middle.

ICICLE

Now, the next word should start with LE and must contain NG in the middle.

LENGTH

Now, the next word should start with TH and must contain RA in the middle.

THRASH

Hence, the required five words are SHIVER, EROTIC, ICICLE, LENGTH, THRASH.

The given number series is 1 8 36 ? 1100 7701

It follows a pattern that,

1

1 x 3 + 5 = 8

8 x 4 + 4 = 36

36 x 5 + 3 = 183

183 x 6 + 2 = 1100

1100 x 7 + 1 = 7701

Hence, the missing number in the given series is 183.

Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r

Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400

q = 1/3 (p + r) => 3q = p + r

Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300

r = 1200 - (p + q) => r = Rs.500.

The given series is 118, 166, 190, 202, 208, ?

118

118 + 48 = 166

166 + 24 = 190

190 + 12 = 202

202 + 6 = 208

208 + 3 = 211

The Ezra Cup is a popular polo tournament conducted annually in India. The Calcutta Polo Club runs this oldest and first ever Polo Trophy. The first Ezra Cup was held in 1880. After a period of inactivity, it has now been revived by Mr. Keshav Bangur, Calcutta Polo Club's president.

The quadratic equation whose roots are reciprocal of 2x2+5x+3=0 can be obtained by replacing x by 1/x.

Hence, 2(1/x)(1/x)+ 5(1/x) + 3 = 0

=> 3x2+5x+2=0