GATE Questions

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504/M = 384/800

(504 x 800) / 384 = M

M = 1050

1/2:1/3:1/4 = 6:4:3

As the difference is 3

=> 3/13x2600 = 600

Let the numbers be p & q

q-p/4 = 4q/6

=> q-4q/6 = p/4

=> 2q/6 = p/4 

=> p/q = 4/3

we can assume that Amar join into business after x months. So Amar money was invest into  (12 – x ) months.

76000×1257000×(12-x)=21

--> 912000 = 114000 ( 12 – x ) = 114 ( 12 – x ) = 912

--> x = 4

After 4 months amar join the business.

From the given diagram,

Tank 10 will be first filled because from tank 1 it will go through tank 4 and tank 10.

We know that 40% = 25

40% of 265 + 35% of 180 = 50% ?

25 x 265 + 35% of 180 = 50% ?

We know that (35% of 180 = 180% of 35) & 180% = 95

25 x 265 + 95 x 35 = 50% ?

106 + 63 = 50% ?

?= 2 x 169 = 338.

Given that,

Members in football team = n(f) = 10

Members in science club = n(s) = 14

Members in both football team and science club = n(f ^ s) = 5

Then, Members in only football team = n(F) = 10 - 5 = 5

Members in only science team = n(S) = 14 - 5 = 9

Hence, members in only football or science team = n(FUS) = n(F) + n(S) - n(f^s) 

= 9 + 5 - 5

= 9.

Hence, many students belong to only science club team or football team = 9.

Let the pipe B be closed after 'K' minutes.

30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16

=> K = 14/16 x 24 = 21 min.