GATE Questions and Answers with Explanation

Q:

If $\log_{7} (2)$ = m, then $\log_{49} (28)$ is equal to ?

A) 1/(1+2m)	B) (1+2m)/2
C) 2m/(2m+1)	D) (2m+1)/2m

Answer & Explanation Answer: B) (1+2m)/2

Explanation:

$\log_{49} (28) = \frac{1}{2 \log_{7} (7 \times 4)}$

= $\frac{1}{2} + \frac{1}{2} (2 \log_{7} (2))$
= $\frac{1}{2} + \log_{7} (2)$
= $\frac{1}{2} + m$
= $\frac{1 + 2 m}{2}$ .

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Q:

Jagan went to another town covering 240 km by car moving at 60 kmph. Then he covered 400km by train moving at 100 kmph and then rest 200 km he covered by a bus moving at 50 kmph. The average speed during the whole journey was ?

A) 36 kmph	B) 35 kmph
C) 72 kmph	D) 70 kmph

Answer & Explanation Answer: D) 70 kmph

Explanation:

By car 240 km at 60 kmph
Time taken = 240/60 = 4 hr.

By train 240 km at 60 kmph
Time taken = 400/100 = 4 hr.

By bus 240 km at 60 kmph
Time taken = 200/50 = 4 hr.

So total time = 4 + 4 + 4 = 12 hr.
and total speed = 240+400+200 = 840 km
Average speed of the whole journey = 840/12 = 70 kmph.

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Q:

A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ?

A) 14 days	B) 18 days
C) 21 deays	D) 16 days

Answer & Explanation Answer: A) 14 days

Explanation:

Let A worked for x days.

x/21 + 4/28 = 1 => x = 18

A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.

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Q:

6 boys and 8 girls can do job in 10 days , 26 boys & 48 women do work in 2 days. Find time taken by 15 boys and 20 girls to do same work ?

A) 2 days	B) 3 days
C) 4 days	D) 5 days

Answer & Explanation Answer: C) 4 days

Explanation:

One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I)

One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II)

Divide both sides by 2 in (I) and then multiply both sides by 5

Now we get, 15b + 20g = 1/4.

Therefore, 15 boys and 20 girls can do the same work in 4 days.

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Q:

The average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 yrs, and B is 5 years younger to C, then find the difference between the age of A and C?

A) 11 yrs	B) 9 yrs
C) 7 yrs	D) 13 yrs

Answer & Explanation Answer: B) 9 yrs

Explanation:

Let the present ages of A and B be 'x' and 'y' respectively

From the given data,

[(x-2) + (y-2)]/2 = 26

=> x+y = 56

But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs

=> x = 35 => y = 56 - 35 = 21

=> Age of B = 21 yrs

Given B is 5 years younger to C,

=> Age of C = 21 + 5 = 26 yrs

=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.

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Q:

An Excel Workbook is a collection of

A) Charts	B) Worksheets
C) Both A & B	D) None of the above

Answer & Explanation Answer: C) Both A & B

Explanation:

An M.S Excel Workbook is a collection of both Worksheets and Charts.

An_Excel_Workbook_is_a_collection_of1558067892.jpg image

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Q:

Main street high school has 10 members on its football team and 14 members on its science club. 5 members at the school belong to both the football and science teams. How many students belong to only science club team or football team?

A) 9	B) 14
C) 24	D) 21

Answer & Explanation Answer: A) 9

Explanation:

Given that,

Members in football team = n(f) = 10

Members in science club = n(s) = 14

Members in both football team and science club = n(f ^ s) = 5

Then, Members in only football team = n(F) = 10 - 5 = 5

Members in only science team = n(S) = 14 - 5 = 9

football_science_teams1533013879.jpg image

Hence, members in only football or science team = n(FUS) = n(F) + n(S) - n(f^s)

= 9 + 5 - 5

= 9.

Hence, many students belong to only science club team or football team = 9.

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Q:

A can write 32 pages in 6 hours and B can write 40 pages in 5 hours. If they write together, in how many hours they can write 110 pages ?

A) 7 hrs	B) 6 hrs 10 min
C) 5 hrs 25min	D) 8 hrs 15 min

Answer & Explanation Answer: D) 8 hrs 15 min

Explanation:

A can write in 1hour = 32/6 pages

Similarly, B in 1 hour = 40/5 pages

Together (A+B) in 1 hour = 32/6 + 40/5 = 40/3

So, A+B write 40/3 pages in 1 hour

A+B write 110 pages in (3/40) x 110 Hours = 8 hours 15 min.

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