GATE Questions

Q:

Car is to garage as aeroplane is to

A) Hangar B) Port
C) Harbour D) Depot
 
Answer & Explanation Answer: A) Hangar

Explanation:

We park car temporarily in garrage, similarly, aeroplane is temporarily parked in hangar.

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Q:

How many birthdays does the average person have?

Answer

Any person can have only 1 birthday i.e, the day he was born. And every year we celebrate it's anniversaries.

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Q:

The length of a rope in meter by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is ?

A) 15 mts B) 30 mts
C) 24 mts D) 36 mts
 
Answer & Explanation Answer: B) 30 mts

Explanation:

The cow can graze an area of 2826 sq.m i.e it is able to cover area of circle of 2826 sq.m

 

Therefore, πr2 =2826
r2 =(2826×7/22) = 899.18 = 900
r = 30 m.

 

Therefore, the radius of the circle implies the length of the rope = 30 mts.

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Q:

A restaurant offers a new promotion of 20% off the original price of cakes, which is Rs. 12. Before the promotion 250 cakes were sold each day. After the promotion, the sale of cakes increases an average of 18% more per day. How much more or less does the restaurant make each day in cakes sales after the promotion?

A) Rs. 185 less B) Rs. 202 more
C) Rs. 175 more D) Rs. 168 less
 
Answer & Explanation Answer: D) Rs. 168 less

Explanation:

Cost of each cake P1 & P2 = Rs. 12

Offer decrease in % = 20%

Increase in sale per day (Q2) = 250 - 18%

Total quantity per day (Q1) = 250

Hence, required change total revenue

TR = P2Q2 - P1Q1 = (12 x 0.8 x 250 x 1.18) -  (12 x 250) = - Rs.168.

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15 7557
Q:

Every year before the festive season, a brand store increases the price of the product by 42% and then introduce two successive discount of 10% and 11% respectively. What is percentage loss and percentage gain ?

A) 3.25% loss B) 13.742% loss
C) 3.25% gain D) 13.742% gain
 
Answer & Explanation Answer: D) 13.742% gain

Explanation:

Let CP = 100,
42 % increase => SP = 142
10 % discount in SP => ((142 x 10)/100) = 14.2
So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.058
2nd SP = (127.8 - 14.058) = 113.742,
So finally CP = 100, SP = 113.742, => gain = 13.742%.

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Q:

A boat whose speed in still water is 9 kmph, goes 12 km downstream and comes back in 3 hrs. Find the speed of the stream?

A) 1 kmph B) 3 kmph
C) 5 kmph D) 4 kmph
 
Answer & Explanation Answer: B) 3 kmph

Explanation:

Let the speed of the stream = x kmph

 

From the given data,

 

 129+x+129-x=3 hrs

3x2 = 27

 

=> x = 3 kmph

 

Therefore, the speed of the stream = 3 kmph

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25 7544
Q:

The oxidation number of Cr in K2Cr2O7 is

A) +6 B) -5
C) +3 D) -4
 
Answer & Explanation Answer: A) +6

Explanation:

We will rewrite the formula as an equation.

2K + 2Cr + 7O = 0

The zero comes from there being no overall charge on the compound.

Each oxidation number is represented by the element's symbol.

Since this compound is not a peroxide or superoxide, the oxidation value for O is -2

K being in group 1 has a +1 charge and therefore has an oxidation number of K is +1

Now, by putting known values in we have:

2(+1) + 2(Cr) + 7(-2) = 0

2 + 2Cr -14 = 0

2Cr = +12

Cr = +6.

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Q:

Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit?

A) 26,250 B) 19,200
C) 18,650, D) 15,200
 
Answer & Explanation Answer: D) 15,200

Explanation:

Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6)

= 7 : 9 : 3

Given Rushi's one year profit = Rs. 5600

=> Let the total profit = Rs. P

Then,

P x 7/19 = 5600

Total profit P = 19 x 5600/7 = Rs. 15,200.

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