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Q:

 83% of 2350 = ?

A) 1889.95 B) 1912.35
C) 1875.25 D) 1950.50
 
Answer & Explanation Answer: D) 1950.50

Explanation:
83% of 2350 = ?
 
83/100 x 2350
 
=8.3 x 235
 
=1950.50
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Filed Under: Percentage
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12 5442
Q:

A sum of money at simple interest amounts to Rs. 415 in 2 years and to Rs. 514 in 4 years. The sum is ?

A) Rs. 316 B) Rs. 251
C) Rs. 154 D) Rs. 294
 
Answer & Explanation Answer: A) Rs. 316

Explanation:

S.I. for 2 years = (514 - 415) = Rs. 99
S.I. for 1 year = 99/2

Principal = (415 - 99) = Rs. 316.

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Filed Under: Simple Interest
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2 5438
Q:

60 percent of 2/7 of three-fourth of a number is 2664. What is the number ?

A) 20720 B) 21352
C) 25421 D) 24150
 
Answer & Explanation Answer: A) 20720

Explanation:

Let N be the required number. 

=> 60100x27x34xN=2664  

=> N = 2664x2x7x5/9  

=> N = 20720.

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Filed Under: Percentage
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10 5438
Q:

Mohan was married 5 years ago. At present his age is 6/5 times of his age at the time of marriage. His wife is 3 year younger to him. Find his wife’s present age?

A) 21 yrs B) 24 yrs
C) 27 yrs D) 30 yrs
 
Answer & Explanation Answer: C) 27 yrs

Explanation:

Let Mohan present age = p

ATQ,

5/6 x p = p - 5

p = 30

His wifes age = 30 - 3 = 27 yrs.

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Filed Under: Problems on Ages
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14 5427
Q:

Rajitha has a calculator, which has 10 digits. She want to clean the calculator by removing all the keys and while reassembling it, she interchanged the locations of 3 pairs of keys. For example, if she placed the key ‘3’ in the place of the key ‘7’, she placed the key ‘7’ only in the place of the key ‘3’ and not any other key. All keys that were interchanged corresponded only to numbers. Later, she input some calculations and obtained outputs as provided in the table below. The input is shown in terms of the keys that Kavitapressed, while the output is the output displayed by the calculator.

Output:

1.   95 + 84=128
2.   128 + 64=195
3.   912 + 43=942
4.   178 + 19=192

Question :

Which of the following pair of digits is unchanged ?

A) 9, 0, 3 B) 1, 3, 8
C) 7, 0, 1 D) 2, 4, 1
 
Answer & Explanation Answer: C) 7, 0, 1

Explanation:
0 1 2 3 4 5 6 7 8 9
0 1 4 8 2 6 5 7 3 9

Here pairs interchanged are

2, 4 

3, 8

5, 6

Unchanged are 0, 1, 7, 9

 

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Filed Under: Arithmetical Reasoning
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11 5423
Q:

Watson bought a book for Rs. 240 and sold to Johny at a profit  of 50%. Johny wants to sell this book to Shekar so that he earns a profit of 25%. But Shekar is adamant at buying this book at a discount of 10%. What marked price should Johny quote to Shekar so as to achieve desired profit ?

A) Rs. 450 B) Rs. 360
C) Rs. 415 D) Rs. 500
 
Answer & Explanation Answer: D) Rs. 500

Explanation:

Watson bought the book for Rs. 240 and sold to Johny at a profit of 50%.

S.P = C.P(1 + P%/100)

=> S.P for Watson = C.P for Johny = 240(1 + 50/100) = 240 x 1.5 = Rs. 360

Let Johny quoted the marked price of the book as Rs. M

We know, SP = M.P(1 - Discount(%)/100)

Here discount = 10% to Shekar,

S.P for Johny = M(1 - 10/100) = 0.9M

But Johny want to earn 25% profit,

=> S.P = C.P(1 + P%/100)

=> 0.9M = 360(1 + 25/100)

=> M = (360x1.25)/0.9

=> M = Rs. 500

Therefore, Johny should quote Rs. 500 as the marked price of the book to get 25% profit and allowing 10% discount to Shekar.

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Filed Under: Profit and Loss
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7 5421
Q:

What will be added to the unit digits of the number 86236 so that number will be divisible by 9  ?

A) 1 B) 2
C) 3 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:

A number is divisible by 9 only if the sum of the digits of the number is divisible by 9.

Here 86236 = 8 + 6 + 2 + 3 + 6 = 25

We must add 2 to 25 to become 27 which is divisible by 9.

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Filed Under: Problems on Numbers
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4 5419
Q:

M, N and O can complete the work in 18, 36 and 54 days respectively. M started the work and worked for 8 days, then N and O joined him and they all worked together for some days. M left the job one day before completion of work. For how many days they all worked together?

A) 4 B) 5
C) 3 D) 6
 
Answer & Explanation Answer: B) 5

Explanation:

Let M, N and O worked together for x days.

From the given data,
M alone worked for 8 days
M,N,O worked for x days
N, O worked for 1 day

But given that
M alone can complete the work in 18 days
N alone can complete the work in 36 days
O alone can complete the work in 54 days

The total work can be the LCM of 18, 6, 54 = 108 units

M's 1 day work = 108/18 = 6 units
N's 1 day work = 108/36 = 3 units
O's 1 day work = 108/54 = 2 units

Now, the equation is
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 - 48
11x = 55
x = 5 days.

Hence, all M,N and O together worked for 5 days.

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Filed Under: Time and Work
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3 5416