GRE Questions

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S.I

= Rs.(1200x10x1/100)

= Rs.120.

C.I

= Rs[(1200x1+5/100)² -1200]

= Rs.123. 

Difference

= Rs.[123-120]

= Rs. 3.

Papayas are yellow due to the presence of carotene and xanthophyll pigments i.e, Caricaxanthin present in the chromoplasts of the fruit pulp.

The coloration of the different tissues in plants is due to the plastids which are present in the cells. Leucoplasts are white in colour, chloroplasts are green in colour and chromoplasts are of various colours. These plastids can take any colour at different time. Therefore, green fruits ( chloroplasts) turn colurful (chromoplasts) at maturity.

13 x 2 = 26 => Z (opposite side)

12 x 2 = 24 => X (opposite side)

13 x 1 = 13 => M (opposite side)

12 x 1 = 12 => L (opposite side)

Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,

part filled by tap X in 1 minute = 1/30

part filled by tap Y in 1 minute = 1/40

Tap Z can empty the tank in 60 minutes. Therefore,

part emptied by tap Z in 1 minute = 1/60

Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24

i.e., the tank can be filled in 24 minutes.

Cup : Coffee :: Bowl : Soup

Because Coffee goes into a Cup and Soup goes into a Bowl where Food is a general thing and Mug is an other utensil. 

So, Cup is to Coffee as Bowl is to Soup.

From the given data,
how many goals scored = 5397....(1)
many more matches = 982.....(2)
he scored five = 163.....(3)
from (1)&(2), many = 9 ....(4)
from (1)&(3), scored = 3 ....(5)
Using (4)&(5)in(1), we get goals = 5 or 7.

Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time T = 211H×30 + Ao minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)

T = 2112×30 + 0o minutes past 2 

=> 11011 minutes past 2

Given total rupees = 20 Rs
No. of one rupee stamps = 3
Now, remaining money = Rs. 17
With that he buys only 2 and 5 rupee stamps
Let number of Rs. 5 stamps = K
Let number of Rs. 2 stamps = L
5K + 2L = 17
K = 3, L = 1 (possible)
L = 6, K = 1 (possible)
=> But given that they are different in number so, K is not equal to 3
one rupee stamps = 3
2 two stamps = 6
5 rupee stamps = 1
Total number of stamps = 10.